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katovenus [111]
3 years ago
8

Type the correct answer in each box.

Chemistry
2 answers:
marin [14]3 years ago
6 0

Answer:

1. 1.414

2. 119.3

Explantation:

zzz [600]3 years ago
5 0

Answer:

0.09 + 1.324 =1.414\\41.0 + 78.3 = 119

Explanation:

The significant figures are the digits of a number that we consider not null. All nonzero digits are significant. The zeros between two numbers (other than zero) are significant. The zeros to the left of the first significant figure are not.

In an operation the result must be expressed with the greatest number of significant figures that have their terms

0.09 + 1.324 =1.414\\41.0 + 78.3 = 119

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Mghso4.5h2O name and molar mass
Usimov [2.4K]
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8 0
4 years ago
What mass of CO is needed to react completely with55.0 g of Fe2O3(s)+CO(g) yield Fe(s)+CO2(g)?
Katarina [22]

Answer:

28.9 g

Explanation:

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Gather all the information in one place</em> with molar masses above the formulas and masses below them.  

M_{r}:     159.69    28.01

              Fe₂O₃ + 3CO ⟶ 2Fe + 3CO₂

Mass/g:  55.0

1. Use the molar mass of Fe₂O₃ to calculate the moles of Fe₂O₃.

\text{Moles of Fe$_{2}$O$_{3}$} =\text{55.0 g Fe$_{2}$O$_{3}$} \times \frac{\text{1 mol Fe$_{2}$O$_{3}$}}{\text{159.69 g Fe$_{2}$O$_{3}$}}= \text{0.3444 mol Fe$_{2}$O$_{3}$}

2. Use the molar ratio of CO:Fe₂O₃ to calculate the moles of CO.

\text{Moles of CO} = \text{0.3444 mol Fe$_{2}$O$_{3}$} \times \frac{\text{3 mol CO}}{\text{1 mol Fe$_{2}$O$_{3}$}}= \text{1.033 mol CO}

3.Use the molar mass of CO to calculate the mass of CO.

\text{Mass of CO} = \text{1.033 mol CO}  \times \frac{\text{28.01 g CO} }{\text{1 mol CO}}= \textbf{28.9 g CO}  

3 0
3 years ago
Read 2 more answers
Will mark brainliest
poizon [28]

Explanation:

solid, liquids and gases are all made up of atoms and molecules

contrast

solids have a definite shape, liquids takes the shape of the container that contains it while gases do not have a shape

solids move about their mean positions, liquids move more freely while gases move in random motion

solids cannot be easily compressed, liquids can be compressed while gases can be easily compressed

5 0
3 years ago
Never mind, question solved.
Alchen [17]
The answer to the problem is 100
5 0
2 years ago
Si desea preparar 300 gramos de una solución de azúcar en agua que tenga una concentración de 20% m/m en cuanto gramos de soluto
Digiron [165]

Answer:

m_{soluto}=60g

Explanation:

¡Hola!

En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:

\%m/m=\frac{m_{soluto}}{m_{solucion}}*100\%

Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:

m_{soluto}=\frac{\%m/m*m_{solucion}}{100\%}\\\\m_{soluto}=\frac{20\%*300g}{100\%}\\\\m_{soluto}=60g

¡Saludos!

5 0
3 years ago
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