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3 years ago

Writing Trig Ratios.

Mathematics

1 answer:

notsponge [240]3 years ago

8 0

Answer:

The ratios are as follows for the given angle:

sineX=opposite/hypotenuse

cosineX=adjacent/hypotenuse

tangentX=opposite/adjacent

Insert the appropriate values for each:

7.) sinZ=24/40

8.) sinC=14/50

9.) cosZ=24/30

10.) tanC=27/36

11.) cosZ=12/15

12.) cosC=27/45

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Question 7(Multiple Choice Worth 75 points) Which of the following is true of all minerals? Made of many different elements Come

algol [13]

The true statement is that minerals come from the ground as crystals. Hope this helps!

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3 years ago

Benjamin has purchased a $105,000 home with a 30-year mortgage at 4.75%.

Lostsunrise [7]

Answer:136 months

Step-by-step explanation:

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3 years ago

Select all sets in which the number

strojnjashka [21]

Answer:

Step-by-step explanation:

a rational number can be expressed as fraction. well, that is what the number 8/9 is.

so, A is a correct option.

as such it is automatically also a member of the real numbers (which is a superset of rational numbers). so, E is a correct option.

all other options are wrong.

8/9 is not a natural number (1, 2, 3, 4, ...).

it is not a whole number (0, 1, 2, 3, 4, ...).

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and as it is a rational number, it is automatically not an irrational number.

7 0

3 years ago

Three out of four students in a school said they would vote for nuncio for class president. Predict how many of the 340 students

Papessa [141]

3/4 = x / 340....3 to 4 students = x to 340 students
cross multiply
(4)(x) = (3)(340)
4x = 1020
x = 1020/4
x = 255 <==

or this way.....

3 out of 4 students.....3/4 = 75%
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4 0

3 years ago

A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac

sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

$N_{t} = N_{0}e^{-\lambda t}$

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant = 0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

$N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g$

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0

3 years ago