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Basile [38]
4 years ago
12

Writing Trig Ratios.

Mathematics
1 answer:
notsponge [240]4 years ago
8 0

Answer:

The ratios are as follows for the given angle:

sineX=opposite/hypotenuse

cosineX=adjacent/hypotenuse

tangentX=opposite/adjacent

Insert the appropriate values for each:

7.) sinZ=24/40

8.) sinC=14/50

9.) cosZ=24/30

10.) tanC=27/36

11.) cosZ=12/15

12.) cosC=27/45

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The answer is 0.4, hope this helps
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There were 93 students out of school of this is 12 % of the total number of students how many students are enrolled at the schoo
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Answer:

the mid point of

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2 years ago
Which statement is true about f(x)-2/3lx+4l-6?
slamgirl [31]
1) Taking in account that the function is f(x)= -(2/3) |x+4|-6, I enclose a file with the graph.

That helps you to conclude:

a) The graph of f(x) has a vertex on (-4, -6)

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7 0
3 years ago
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Juan paga por un saco S/ 224, después de que le han
grigory [225]

El saco tiene un precio original de 400 soles.

<h3>¿Cómo determinar el precio inicial de un saco comprado con descuento?</h3>

En este problema tenemos el caso de un precio de compra (P'), en soles, que es resultado de aplicar dos descuentos consecutivos al precio original del saco (P), en soles. El precio es el resultado de multiplicar el precio original por los dos factores de porcentaje, descrito por la siguiente fórmula:

P' = P · (1 - r₁ / 100) · (1 - r₂ / 100), 0 ≤ r₁, r₂ ≤ 100.

Donde:

  • r₁ - Porcentaje del primer descuento.
  • r₂ - Porcentaje del segundo descuento.

Si sabemos que P' = 224, r₁ = 30 y r₂ = 20, entonces el precio original del saco es:

224 = (1 - 30 / 100) · (1 - 20 / 100) · P

224 = 0.7 · 0.8 · P

P = 224 /(0.7 · 0.8)

P = 400

El precio original del saco es de 400 soles.

Para aprender más sobre descuentos: brainly.com/question/24130820

#SPJ1

5 0
1 year ago
Hi can someone please help me? :( im not sure where im going wrong. ty!!
lisabon 2012 [21]

The triangle ABC is a right angled triangle , right angled at C because it is the angle subtended by the diameter

Now OA = OB = OC = 4 cm (radii)

AB = OA + OB = 8 cm

By pythagoras theorem ,

AB^2 - BC^2 = AC^2

\sqrt{64 - 16} = AC

AC =4 \sqrt3

shade region area = area of semicircle - area of triangle

= 1/2 \pi r^2 - 1/2 × base × height

=1/2 × 16 \pi - 1/2 × 4 × 4\sqrt3

=8\pi - 8\sqrt3

=8(\pi - \sqrt3)

8 0
3 years ago
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