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3 years ago

Writing Trig Ratios.

Mathematics

1 answer:

notsponge [240]3 years ago

8 0

Answer:

The ratios are as follows for the given angle:

sineX=opposite/hypotenuse

cosineX=adjacent/hypotenuse

tangentX=opposite/adjacent

Insert the appropriate values for each:

7.) sinZ=24/40

8.) sinC=14/50

9.) cosZ=24/30

10.) tanC=27/36

11.) cosZ=12/15

12.) cosC=27/45

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Express.as decimal numerals nine and two hundred thirty five thousnadths

notka56 [123]

The answer is 9.235. Hope that helped

4 0

3 years ago

jamal bought donuts and cupcakes. he bought three times as many donuts as cupcakes. cupcakes cost .50 cent each and donuts cost

vovangra [49]

Answer: He bought 4 cupcakes and 12 donuts

Step-by-step explanation:

He bought three times as many donuts as cupcakes so we could represent that by the equation d= 3c where d is donuts and c is the cupcakes.

If cupcakes also cost 50 cent and donuts cost a dollar each and he spent a total of 10 dollars then we could also represent that by the equation

0.50d + 1c = 10

Now combine use the two equations and solve for d and c

d= 3c

0.50d + 1c =10 substitute d in the first equation into the second equation.

0.50(3c) + 1c =10

1.5c + 1c =10

2.5c = 10

c= 4

In this case he bought a total of 4 cupcakes and to find the total of donuts that he bought we multiply that by 3 because he bought three times as much as that.

d= 3 * 4

d = 12

3 0

3 years ago

Suppose that 65% of the people who inquire about investments at a certain brokerage firm end up investing in stocks, 38% end up

Effectus [21]

Answer:

0.67 = 67% probability that a person who inquires about investments at this firm will invest in stocks or bonds (or both).

Step-by-step explanation:

This question is solved treating these probabilities as Venn events.

I am going to say that:

Event A: Person invests in stocks.

Event B: Person invests in bonds.

65% of the people who inquire about investments at a certain brokerage firm end up investing in stocks

This means that $P(A) = 0.65$

38% end up investing in bonds

This means that $P(B) = 0.38$

36% end up investing in both stocks and bonds.

This means that $P(A \cap B) = 0.36$

What is the probability that a person who inquires about investments at this firm will invest in stocks or bonds (or both)?

This is $P(A \cup B)$ , given by the following equation:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

Considering the values we have for this problem:

$P(A \cup B) = 0.65 + 0.38 - 0.36 = 0.67$

0.67 = 67% probability that a person who inquires about investments at this firm will invest in stocks or bonds (or both).

5 0

3 years ago

A box of candy bars cost $3.12. Each candy bar in the box cost $0.52. How many candy bars are in the box

tatiyna

3.12/.52=6
6 candy bars in a box

Hope I got it right for your sake.

3 0

3 years ago

Geometry problem: Find the distance between the parallel lines y=-3/2x+1 and 2y+3x=10

s344n2d4d5 [400]

Answer:

d = 1.847

Step-by-step explanation:

To avoid any ambiguity, please enclose the slope -3/2 inside parentheses:

y = (-3/2)x + 1. Next, solve the 2nd equation for y: 2y = - 3x + 10 => y = (-3/2)x + 5. Notice how these two lines have the same slope (-3/2)? Thus, the two given lines are parallel.

It's important to realize that the distance between these two lines is a line segment with perpendicular to both lines. Thus, the segment representing this distance has the form y = (2/3)x + c. Let's say that this segment passes through the y-intercept of y = (-3/2)x + 1; it thus passes through (0,1), and thus has the equation y = (2/3)x + 1.

Find the point at which this y = (2/3)x + 1 intersects the line y = (3/2)x + 5. Note that the xresultant point

Setting these two equations = to one another results in (2/3)x + 1 = (-3/2)x + 5.

Multiplying both sides by the LCD (6) will eliminate the fractions:

4x + 6 = -9x + 30. Combining like terms: 13x = 24, and x = 24/13 = 1.846.

Substitute this x-value into y = (2/3)x + 1 to find the y-coordinate of the point of intersection of y = (2/3)x + 1 and y = (-3/2)x + 5:

When x = 1.846, y = (2/3)(1.846) + 1 = 1.231.

Thus, the desired distance is that between (0,1) and (1.846, 1.231), and is:

d = √ [ (1.846 - 0)^2 + (1.231 - 1)^2 ] = √ [ (1.846)^2 + (0.053)^2 ]

This simplifies to d = √ [ 3.408 + 0.003 ] = √3.411, or

d = 1.847 (answer)

7 0

3 years ago