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natta225 [31]
3 years ago
13

The expression (2x+1)^2 -2(2x^2-1) is equivalent to:

Mathematics
1 answer:
Leni [432]3 years ago
8 0
(2x + 1)^2 - 2(2x^2 - 1) = 4x^2 + 4x + 1 - 4x^2 + 2 = 4x + 3
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Point Tis on line segment SU. Given TU = 4x + 1, SU = 8, and ST = 3x,
Harrizon [31]

Answer:

5 units

Step-by-step explanation:

If point T is on the line segment SU, then ST + TU = SU.

Given

TU = 4x + 1

SU = 8

ST =  3x

To get TU, we need to get the value of x first. To get x, we will substitute the given parameters into the formula;

3x+4x+1 = 8

7x+1 = 8

subtract 1 from both sides

7x+1-1 = 8-1

7x = 7

divide both sides by 7

7x/7 = 7/7

x = 1

Substitute x = 1 into the length TU

Since TU = 4x+1

TU = 4(1)+1

TU = 5

Hence the numerical length of TU is 5 units

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3 years ago
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Answer:

  y was not substituted for every x

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Here, f(x) = x^2 +12x, so f(y) = y^2 +12y

This is not the expression we see on the right of ...

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Apparently y was not properly substituted into f(x).

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Find the length of segment AB
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Step-by-step explanation:

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