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natta225 [31]
3 years ago
13

The expression (2x+1)^2 -2(2x^2-1) is equivalent to:

Mathematics
1 answer:
Leni [432]3 years ago
8 0
(2x + 1)^2 - 2(2x^2 - 1) = 4x^2 + 4x + 1 - 4x^2 + 2 = 4x + 3
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4 0
3 years ago
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I need help ASAP!!Please explain how to solve the problem
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Answer:

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As i previously explained,

The general form of equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2.

h and k are the co-ordinates of the center of circle and r is the radius

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Now,

( x - h )^2 + ( y - k )^2 = r^2

or,( x - 2 )^2 + ( y - 1 )^2 = r^2

The radius of the circle is 1 units(from figure)

So, put that in, we get

( x - 2 )^2 + ( y - 1 )^2 = 1^2

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You can simplify this or leave it here.

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