Answer:
He needs to sell the rest of the oranges at 75 paisa each.
Step-by-step explanation:
Consider the given information that, Shishir bought 4000 orange at 70 paisa each.
Note: 1 rupees = 100 paisa
Thus, 70 paisa = 70/100 rupees = 0.70 rupees
Therefore, the cost price of 4000 oranges is:
4000×0.70 rupees = 2800 rupees
The selling price of 2000 oranges is:
2000×0.90 rupees = 1800 rupees
The number of oranges now Shishir have:
4000 - 2000 - 400 = 1600
He wants to make a profit of RS 200. Thus the selling price of 4000 oranges should be:
2800 rupees + 200 rupees = 3000 rupees
He earned 1800 rupees by selling 2000 oranges at 90 paisa. So, the remaining amount that he needs to make with 1600 oranges is:
3000 rupees - 1800 rupees = 1200 rupees
Therefore, the cost of one orange is:
1600 oranges = 1200 rupees
1 orange = 1200/1600 rupees
1 orange = 0.75 rupees
Hence, he needs to sell the rest of the oranges at 75 paisa each.
![3 x^{2} +1- [1-x]](https://tex.z-dn.net/?f=3%20x%5E%7B2%7D%20%2B1-%20%20%5B1-x%5D)
