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4 years ago

How do sound waves transfer energy?

Chemistry

1 answer:

bazaltina [42]4 years ago

8 0

Answer:

By the vibration of particles in a medium

Explanation:

For example, the energy in sound waves is transferred by the vibration of the molecules in air.

A is wrong. Electromagnetic radiation transfers energy through vibrating electric and magnetic fields.

B is wrong. Sound waves can transfer energy far from the ocean.

C is wrong. A combination of waves just makes a wave with a different shape.

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Identify each of these substances as acidic, basic, or neutral.

SpyIntel [72]

Answer:pure water is neutral . Lake water is acidic. Baking soda and soapy water are basic.

Explanation: 7 is neutral. The higher on the ph scale like 1-6 is acidic. The lower on the scale 8-13 is base or alkaline.

4 0

3 years ago

Read 2 more answers

Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

$\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\ \frac{m_{S} }{m_{O} }= 2$

Let us express it as

$SO_{\frac{m_{S} }{m_{O} }} = 2$

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

$\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\ \frac{m_{S} }{m_{O} }= 1$

Let us express it as

$SO_2_{\frac{m_{S} }{m_{O} }}= 1$

Now, for the ratio of both the above-calculated ratios,

$\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}$

The required ratio is 2:1

3 0

3 years ago

A d1 octahedral complex is found to absorb visible light, with the absorption maximum occurring at 503 nm. calculate the crystal

Nina [5.8K]

237.9 KJ/mol⁻¹ crystal-field splitting energy is found to absorb visible light.

<h3>What is crystal-field splitting energy?</h3>

The energy of the electron configuration in the ligand field less the energy of the electronic configuration in the isotropic field is known as the crystal field energy.

The core metal ion's d orbitals split into two groups with various energies in an octahedral complex. The energy of the electron transition, which is related to the wavelength of the emitted light, is equal to the energy of the crystal-field splitting.

Δ = E = ℎ c / λ

Where,

where ℎ is the Planck constant, 6.62*10⁻³⁴m²kg s⁻¹, and c is the speed of light, 3 x 10⁸m s⁻¹.

Δ = 6.62*10⁻³⁴m²kg s⁻¹ / 503 x 10⁻⁹

= 3.95 x 10⁻¹⁹

= 3.95 x 10⁻¹⁹

This value is the splitting energy per ion.

To convert it to J/mol, we should multiply it by Avogadro number, 6.022 x 10²³mol⁻¹

= 3.95 x 10⁻¹⁹ x 6.022 x 10²³mol⁻¹

= 237.9 KJ/mol⁻¹

Therefore, the crystal-field splitting energy is 237.9 KJ/mol⁻¹ .

Learn more about crystal-field splitting energy, Here:

brainly.com/question/27295962

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8 0

2 years ago

The water that moves over the land is and carries particales is a called a

yulyashka [42]

It is called a runoff

3 0

3 years ago

The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 2.001 g sample of B

Alborosie

Answer: The empirical formula for the given compound is $C_{15}H_{24}O_1$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=5.995g$

Mass of $H_2O=1.963g$

Mass of sample = 2.001 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 5.995 g of carbon dioxide, $\frac{12}{44}\times 5.995=1.635g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.963 g of water, $\frac{2}{18}\times 1.963=0.218g$ of hydrogen will be contained.

Mass of oxygen in the compound = (2.001) - (1.635 + 0.218) = 0.148 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.635g}{12g/mole}=0.136moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.218g}{1g/mole}=0.218moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.148g}{16g/mole}=0.0092moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0092 moles.

For Carbon = $\frac{0.136}{0.0092}=14.78\approx 15$

For Hydrogen = $\frac{0.218}{0.0092}=23.69\approx 24$

For Oxygen = $\frac{0.0092}{0.0092}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 15 : 24 : 1

Hence, the empirical formula for the given compound is $C_{15}H_{24}O_1$

3 0

4 years ago