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vladimir1956 [14]
3 years ago
13

Which one of the following scenarios accurately describes a condition in which resonance can occur? A. A column of air has a hei

ght equal to 1⁄8 of the wavelength of the sound waves produced by a tuning fork vibrating over the column of air in an open pipe that's partially immersed in water. B. A pipe's length is equal to 1⁄2 of the wavelength of the sound waves produced by a tuning fork vibrating over one end of the pipe that's open to the air at both ends. C. A person is holding a tuning fork on one end of a football field and another person is holding a separate tuning fork on the opposite end of the field. D. A vibrating tuning fork is struck and begins to vibrate as the object used to strike it is placed away from the tuning fork.
Physics
1 answer:
Butoxors [25]3 years ago
4 0
The correct option is B.
Resonance is said to occur when one object which is vibrating at the same natural frequency of a second object forces the second object into vibrational motion. When resonance is achieved a big loud voice is usually heard. Resonance generally requires three conditions to occur:
1. An object that has a natural frequency.
2. A force that is functioning at the same frequency as the natural frequency.
3. Prevention of energy loss.
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Two boxes sit side by side on a smooth horizontal surface. The lighter box 5.2 kg, the heavier box has a mass of 7.4kg (a) find
Paladinen [302]

OK.  So you're pushing on the small box, and on the other side of it, the small
box is pushing on the big box. So you're actually pushing both of them.

-- The total mass that you're pushing is (5.2 + 7.4) = 12.6 kg.

-- You're pushing it with 5.0N of force.

-- Acceleration of the whole thing = (force)/(mass) = 5/12.6 = <em>0.397 m/s²</em> (rounded)

-- Both boxes accelerate at the same rate. So the box farther away from you ...
the big one, with 7.4 kg of mass, accelerates at the same rate.

The force on it to make it accelerate is (mass) x (acceleration) =

                                                              (7.4 kg) x (5/12.6 m/s²) =  <em>2.936 N.</em>

The only force on the big box comes from the small box, pushing it from behind. 
So that same  <em>2.936N</em>  must be the contact force between the boxes.

8 0
2 years ago
An object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m
Svetllana [295]

The magnitude of the work done by force experience by the object is (2a²b + 3b²)J.

<h3>Work done by the force experienced  by the object</h3>

The magnitude of the work done by force experience by the object is calculated as follows;

W = f.d

where;

  • F is the applied force (2xyi + 3yj), where x and y are in meters
  • d is the displacement of the object = (a, b)

The work done by the force is determined from the dot product of the force and the displacement of the object.

F = (2xyi + 3yj).(a + b)

W = (2abi + 3bj).(ai + bj)

W = (2a²b + 3b²)J

Thus, the magnitude of the work done by force experience by the object is (2a²b + 3b²)J.

The complete question is below:

The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.

How much work does the force do?

Learn more about work done here: brainly.com/question/8119756

5 0
2 years ago
What is the horsepower of a 1,500 kg car that can go to the top of a 360 m high hill in exactly 1 min?
Airida [17]

Answer:

W = m g h        work that must be done on car

P = W / t       power that must be input (in Watts)

P = m g h / t = 1500 kg * 9.8 m/s^2 * 360 m /  60 sec

P = 88,200 watts

P = 88,200 watts / 746 watts / hp = 118 hp

7 0
1 year ago
If a bust starts to move and its velocity becomes 90 km after 8 seconds . calculate its acceleration answer it quick please
kherson [118]

Answer:

a = 3.125 [m/s^2]

Explanation:

In order to solve this problem, we must use the following equation of kinematics. But first, we have to convert the speed of 90 [km/h] to meters per second.

90\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}   \\= 25 \frac{m}{s}

v_{f} =v_{i} + (a*t)

where:

Vf = final velocity = 25 [m/s]

Vi = initial velocity = 0

a = acceleration [m/s^2]

t  = time = 8 [s]

The initial speed is zero as the bus starts to koverse from rest. The positive sign of the equation means that the bus increases its speed.

25 = 0 + a*8

a = 3.125 [m/s^2]

3 0
3 years ago
Can someone help??
Paul [167]

Answer:

F = 2520 N

Explanation:

We have,

The maximum acceleration of a fist in a karate punch is 4200 m/s². The mass of the fist is 0.6 kg.

It is required to find the force that the wood place on the fist. Force is given by the product of mass and its acceleration such that,

F = ma

F=0.6\times 4200\\\\F=2520\ N

So, the force of 2520 N is acting on the wood.

8 0
3 years ago
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