Answer:
The peak emf generated by the coil is 2.67 V
Explanation:
Given;
number of turns, N = 940 turns
diameter, d = 24 cm = 0.24 m
magnetic field, B = 5 x 10⁻⁵ T
time, t = 5 ms = 5 x 10⁻³ s
peak emf, V₀ = ?
V₀ = NABω
Where;
N is the number of turns
A is the area
B is the magnetic field strength
ω is the angular velocity
V₀ = NABω and ω = 2πf = 2π/t
V₀ = NAB2π/t
A = πd²/4
V₀ = N x (πd²/4) x B x (2π/t)
V₀ = 940 x (π x 0.24²/4) x 5 x 10⁻⁵ x (2π/0.005)
V₀ = 940 x 0.04524 x 5 x 10⁻⁵ x 1256.8
V₀ = 2.6723 V = 2.67 V
The peak emf generated by the coil is 2.67 V
Answer:
∑Fy = 0, because there is no movement, N = m*g*cos (omega)
Explanation:
We can solve this problem with the help of a free body diagram where we show the respective forces in each one of the axes, y & x. The free-body diagram and the equations are in the image attached.
If the product of mass by acceleration is zero, we must clear the normal force of the equation obtained. The acceleration is equal to zero because there is no movement on the Y-axis.
Answer:
The speed of the large cart after collision is 0.301 m/s.
Explanation:
Given that,
Mass of the cart, 
Initial speed of the cart, 
Mass of the larger cart, 
Initial speed of the larger cart, 
After the collision,
Final speed of the smaller cart, 
(as its recolis)
To find,
The speed of the large cart after collision.
Solution,
Let 
is the speed of the large cart after collision. It can be calculated using conservation of momentum as :
So, the speed of the large cart after collision is 0.301 m/s.
To calculate the mass of the fuel, we use the formula
Here, m is the mass of fuel, V is the volume of the fuel and its value is 
and 
is the density and its value of 0.821 g/mL.
Substituting these values in above relation, we get
Thus, the mass of the fuel 247 .94 kg.
Answer:
Rotating the loop until it is perpendicular to the field
Explanation:
Current is induced in a conductor when there is a change in magnetic flux.
The strength of the induced current in a wire loop moving through a magnetic field can be increased or decreased by the following methods:
By increasing the strength of the magnetic field there will be increased in the induced current. If the strength of the magnetic field is decreased then there is a decrease in induced current.
By increasing the speed of the wire there will be increased in the induced current. When the speed of the wire is decreased then there is a decrease in induced current.
By increasing the number of turns of the coil the strength of the induced current can be increased. when there is less number of turns in coils then there is a decrease in induced current.
Rotating the loop until it is perpendicular to the field will not increase the current induced in a wire loop moving through a magnetic field.
Therefore, the option is (c) is correct.
