How should the student use the data collected and the known quantities from the experiment to determine the initial total mechan
1 answer:
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Answer:
Wavelength,
Explanation:
The energy of the electron in a hydrogen atom can be calculated from the Bohr formula as :
.............(1)
Where
R is the Rydberg constant
n is the number of orbit
We need to find the wavelength of the line in the absorption line spectrum of hydrogen caused by the transition of the electron from an orbital with to an orbital with n₁ = 2 to an orbital with n₂ = 3.
Equation (1) can be re framed as :
or
So, the the wavelength of the line in the absorption line spectrum is 657 nm. Hence, this is the required solution.
Answer:
A) F(r) = [12a/(r^(13))] - [6b/(r^(7))]
ii) Graphs are attached
B) Equilibrium Distance = (2a/b)^(1/6)
C) Minimum Energy = b²/4a
D) a = 6.67 x 10^(-138) Jm^(12)
b = 6.41 x 10^(-78) Jm^(6)
Explanation:
I've attached the explanation of A-C alongside the graphs
D) i) From the question, we are to make r equal to the derivative of "r" we got when F(r) = 0 which was r = (2a/b)^(1/6)
Thus, since we are given equilibrium distance as: 1.13 x 10^(-10), hence;
(2a/b)^(1/6) = 1.13 x 10^(-10)m
So, (2a/b)= [1.13 x 10^(-10)]^(6)
a = (b/2)[1.13 x 10^(-10)]^(6)
From earlier, we saw that b²/4a = U(r)
Thus since U(r) = 1.54 x 10^(-18) from the question, b²/4a = 1.54 x 10^(-18)
Putting a = (b/2)[1.13 x 10^(-10)]^(6);
We have;
(b²) / [(4b/2)[1.13 x 10^(-10)]^(6)]] = 1.54 x 10^(-18)
b/2 = [1.13 x 10^(-10)]^(6)] x 1.54 x 10^(-18)
So, b = 6.41 x 10^(-78) Jm^(6)
ii) Putting (6.41 x 10^(-78))² for b in;
a = (b/2)[1.13 x 10^(-10)]^(6)
We have, a = (6.41 x 10^(-78))²/ ( 4 x 1.54 x 10^(-18)
So a = 6.67 x 10^(-138) Jm^(12)
Answer:
Explanation:
The formula for angular momentum is
L = mvr where L is the angular momentum, m is the mass of the object, v is the velocity of the object, and r is the radius of the object. The problem we have that prevents us from just throwing those numbers in there is that mass has to be in kg and it's not, and radius has to be in meters and it's not.
Changing the mass to kg:
750 g = .750 kg
Changing the radius to m:
35 cm = .35 m
Now we can fill in the variables with their respective values:
L = .750(10.0)(.35) gives us