A real battery with internal resistance 0.460 Ω and emf 9.00 V is used to charge a 56.0-µF capacitor. A 21.0-Ω resistor is put i n series with the battery and the capacitor when charging. (a) What is the time constant for this circuit?
2 answers:
Given Information:
Internal resistance of battery = 0.460
Resistance = 21.0 Ω
Capacitance = 56.0 µF
Required Information:
time constant = τ = ?
Answer:
τ = 0.0012
Explanation:
The time constant τ provides the information about how long it will take to charge the capacitor up to certain level.
τ = Req*C
Where Req is the equivalent resistance and C is the capacitance.
Req = R + r
Where R is the resistance of the resistor and r is the internal resistance of the battery.
Req = 21.0 + 0.460 = 21.460 Ω
τ = Req*C
τ = 21.46*56x10⁻⁶
τ = 0.0012
A capacitor approximately charges to 63% in one τ and about 99% in 5τ
Answer: 1.176×10^-3 s
Explanation: The time constant formulae for an RC circuit is given below as
t =RC
Where t = time constant , R = magnitude of resistance = 21 ohms , C = capacitance of capacitor = 56 uf = 56×10^-6 F
t = 56×10^-6 × 21
t = 1176×10^-6
t = 1.176×10^-3 s
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