Answer:
i = 0.5 A
Explanation:
As we know that magnetic flux is given as

here we know that
N = number of turns
B = magnetic field
A = area of the loop
now we know that rate of change in magnetic flux will induce EMF in the coil
so we have

now plug in all values to find induced EMF


now by ohm's law we have


Answer:
Yes
Explanation:
The spring force is given as:
F = kd
F is the spring force
K is the spring constant
d is the magnitude of the stretch
Since k is a constant, therefore, doubling the stretch distance will double the force.
Both stretch distance and force applied can be said to be directly proportional to one another.
Answer: The light bends because light travels fast but it slows down in a denser medium. For example light refracts in water or it bends after passing through air. When light passes through air ( a less dense medium ) then through water ( a more dense medium ) the beam of light bends because light travels more slowly in a denser medium then it picks up its pace again once it passes. The density of the substance determines how much the light is refracted. I hope this makes sense and I hope this answered your question!! :)
To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,
The circumference of the planet is,

Under the mathematical value the radius would be



Using second equation of motion

Replacing the values given,

Rearranging and solving for 'a' we have,

Using the value of acceleration due to gravity from Newton's law we have that

Here,
r = Radius of the planet
G = Gravitational Universal constant
M = Mass of the Planet


Therefore the mass of this planet is 
Answer:
0.92 μC
Explanation:
In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:

or 0.92 μC