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Minchanka [31]
3 years ago
15

7. If 8 million kg of water flows over Niagara Falls each second, calculate the power available at the bottom of the falls.

Physics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

The power will be "3.92×10⁹ Watts". A further explanation is given below.

Explanation:

The given values as per the question,

Rate,

= 8 million kg

Distance,

= 50 m

Gravity,

= 9.8 m/s²

As we know,

The power will be:

⇒ Power = Rate\times Distance\times  Gravity

On putting the values, we get

⇒             =  8\times 10^6\times 50\times 9.8

⇒             =3.92\times 10^9 \  Watts

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3 years ago
By what factor will the acceleration of an object change its mass stays constant but the force acting on it triples
Viktor [21]

Answer:

lacceleration is given by

a=F/m

With force acting on the object remained constant ,the acceleration is inversly proportional to mass of the object i.e with increase in mass =>acceleration decreases and with decrease in mass => acceleration increases.

a)

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b)

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7 0
3 years ago
Six artificial satellites circle a space station at a constant speed. The mass m of each satellite, distance L from the space st
damaskus [11]

Answer:

The answer to the question is;

Based on their acceleration the rank of the satellites from largest to smallest is.

B   >→   A   >→    E   >→    C    >→     F    >→     D.

Explanation:

Acceleration is given by \frac{v^2}{r}

Therefore the acceleration for each of the satellite is given by

Satellite A)      \frac{160^2}{5000} =    5.12 m/s²

Satellite B)      \frac{160^2}{2500}  =   10.24 m/s²

Satellite C)      \frac{80^2}{2500}   =  2.56 m/s²

Satellite D)      \frac{40^2}{10000}  =  0.16 m/s²

Satellite E)       \frac{120^2}{5000}   =  2.88 m/s²

Satellite F)       \frac{80^2}{10000}  = 0.64 m/s²

Therefore in order of decreasing acceleration, from largest to smallest we have

Satellite B) > Satellite A) >Satellite E) >Satellite C)>Satellite F)>Satellite D).

3 0
3 years ago
Read 2 more answers
What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newt
ipn [44]
Hope this helps you!

5 0
3 years ago
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A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.
pogonyaev

Answer:

1.40 N

Explanation:

The magnitude of the frictional force is given by:

F=\mu N

where

\mu is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is \mu=0.012. The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

N=65 N+52 N=117 N

Therefore, the frictional force is

F=\mu N=(0.012)(117 N)=1.40 N

3 0
3 years ago
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