Answer:
No .
Explanation:
The vapor pressure of water at room temperature is .0313 atom or 3.13 kPa.
To make a liquid boil, its vapor pressure must be equal to pressure around it.
So pump must create pressure of 3.13 k Pa or less to make water attain its stage of boiling at room temperature. As the motor can not produce pressure lesser than 15 k Pa , pump will not be able to make water boil at room temperature.
Answer is: 124135 J.
m(water) = 55g.
T(water) = 100°C.
Q = ?
Q - heat needed to convert water to steam.
∆Hvap = 2257 J/g
∆Hvap - enthalpy of vaporization is the amount of energy <span> needed to transform the liquid substance into a gas.
Q = </span>∆Hvap · m(water) = 2257 J/g · 55g = 124135 J.
To consider the molecule in gas at rest, suppose a container of gas at rest.
We know that velocity is a vector quantity and it includes direction but speed is a scalar quantity and it does not include a direction.
Although the molecules are moving around a lot, they are only moving around within the fixed walls of the container. As the container isn't moving (given), the net velocity of the gas molecules is zero. Think about their random movements as vectors, then think about adding up all those vectors over time. They cancel each other out over time. So, the average velocity of a molecule in gas at rest is zero.
But it's only the directions that cancel each other out, which is why the average speed (ignoring direction) is non-zero.
To learn more about average speed refer to the link:
brainly.com/question/12322912
#SPJ4
Answer:
the magnitude is 7 and sign of the point charge on the surface shell is -13
Explanation:
Answer:
C. 1.43 m/s
Explanation:
Velocity = displacement / time
v = (1 m − -9 m) / 7 s
v = 1.43 m/s