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sdas [7]
3 years ago
10

A supercell thunderstorm may have a distinctive shape like _____.

Chemistry
1 answer:
liq [111]3 years ago
8 0
D. Pinwheel probably because think it’s a thunderstorm and supercells mean they are super big thunderstorms so I guess D
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How many moles of silicon are in 5.9 X 10 to the 24 power atoms of silicon​
Dimas [21]

Answer:

9.79740949850 moles

Explanation:

  • 1 mole = Avogardo's Number <<6.022 E 23 <<particles, atoms, etc.>>
  • This problem can be solved using dimensional analysis by multiplying atoms (5.9E24 atoms) by (1) mole and then dividing the number by Avogardo's number (6.022 E 23 atoms).
  • Note: E = * 10

Side Note: Please let me know if you need any clarifications about this!

8 0
2 years ago
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A gas has a volume of 240 mL and a pressure of 0.99 atm. If the pressure is decreased to 0.951 atm, what is the new volume of th
irakobra [83]

V2 = 250 ml

Explanation:

Given:

P1 = 0.99 atm. V1 = 240 ml

P2 = 0.951 atm. V2 = ?

We can use Boyle's law to solve for V2

P1V1 = P2V2

V2 = (P1/P2)V1

= (0.99 atm/0.951 atm)(240 ml)

= 250. ml

6 0
2 years ago
How does the muscular and nervous system work together to help maitain homeostasis
Inessa [10]
The nervous system sends signals to the muscles to shiver when our body temperature begins to drop to a lower than normal temperature. the slight movement of the muscles will work to bring temperature back to homeostasis
7 0
3 years ago
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Which statement is correct about the rate of a chemical reaction? (5 points)
Elza [17]

Answer:

they don't depend on the temperature

6 0
3 years ago
A 72.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by a
Aliun [14]

Answer: 0.20 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 1.40 M

V_1 = volume of stock solution = 72.0 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = 248 ml

1.40\times 72.0=m\times 248

m=0.41M

Now 124 mL portion of this prepared solution is diluted by adding 133 mL of water.

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.41 M

V_1 = volume of stock solution = 124 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = (124 +133) ml = 257 ml

0.41\times 124=m\times 257

m=0.20M

Thus the final concentration of the solution is 0.20 M.

8 0
3 years ago
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