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sdas [7]
3 years ago
10

A supercell thunderstorm may have a distinctive shape like _____.

Chemistry
1 answer:
liq [111]3 years ago
8 0
D. Pinwheel probably because think it’s a thunderstorm and supercells mean they are super big thunderstorms so I guess D
You might be interested in
Two solutions are created by mixing one solution containing lithium nitrate with one containing sodium phosphate.
babunello [35]

Answer:

Solution A that will form a precipitate with Ksp = 2.3 x 10−4

Explanation:

                                  Li₃PO₄ ⇄ 3 Li⁺(aq) + PO₄³⁻(aq)

                                                     3S               S

Where S = Solubility(mole/lit) and Ksp = Solubility product

⇒ Ksp = (3S)³ x (S)

⇒ 27S⁴ = 2.3x10−4

⇒ S = 0.05 mol/lit

Concentration of Li₃PO₄ precipitate = 0.05

<u>Solution A </u>

0.500 lit of a 0.3 molar LiNO₃ contains 0.5 x 0.3 = 0.15 mole

0.4 lit of a 0.2 molar Na₃PO₄ contains = 3 x 0.4 x 0.2 = 0.24 mole

                                     3 LiNO₃ + Na₃PO₄ → 3 NaNO₃ + Li₃PO₄

(Mole/Stoichiometry)    \frac{0.15}{3}                \frac{0.24}{1}

                                   = 0.05            = 0.24

Since from (Mole/Stoichiometry) ratio we can conclude that LiNO₃ is limiting reagent.

So concentration of Li₃PO₄ is equal to 0.05.

                       

6 0
2 years ago
As more bulbs are connected in series in a circuit, what happens to the brightness with which each glows?
madam [21]
They dim unless more volts are added (batteries")
8 0
2 years ago
Read 2 more answers
What is the pH of a solution with a concentration of 4.7 × 10-4 molar H3O+?
wlad13 [49]
The pH of a liquid substance is calculated through the equation,
                                       pH = -log[H3O+]
Substituting the given concentration of the hydronium ion to the equation above,
                                        pH = -log[4.7x10^-4 M]
The value of pH is equal to 3.33. Thus, the pH of the solution is approximately 3.33. 
3 0
3 years ago
Question 1 (1 point)
ladessa [460]

Answer:D - adding a catalyst

Explanation:

4 0
3 years ago
An element consists of two isotopes. One with a mass of 79.95 amu and an abundance of 29.9%. The second isotope has a mass of 81
galina1969 [7]

 the molar  mass of the element  is  81.36 g/mol

<u><em>calculation</em></u>

step 1 : multiply  each %abundance  of the isotope  by   its mass  number

that is 79.95 x 29.9 =2391

           81.95 x 70.1  = 5745

Step 2: add them together

2390.5 + 5744.7 =8136

Step 3: divide by 100

= 8136/100 = 81.36  g/mol

5 0
3 years ago
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