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andrey2020 [161]
3 years ago
8

Amorphous solids do not possess overall order, with individual clusters held together only by Van der Waals forces.

Chemistry
2 answers:
wolverine [178]3 years ago
8 0
The answer is true. Amorphous solids, also known as non-crystalline solid, lacks a long-range order seen in a crystalline solid. Examples are glass. polymers and silicon. Many solids around are in an amorphous form.
zheka24 [161]3 years ago
4 0

Answer:

True

Explanation:

Amorphous solid is the designation given to a structure that has no long-range (atomic) spatial ordering, such as regular solids. For a material to be considered as regular solid it must have a defined crystalline structure, which corresponds to a positioning of the atoms that compose it. Amorphous materials have no definite geometric shape, may even have some rigidity like ordinary solids, but their atoms are not in spatial organization (at the microscopic level), in which case amorphous solids have no general order, with individual clusters joined together only. by the forces of Van der Waals.

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What is the difference between qualitative data and quantitative data?
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Quantitative data can be counted, measured, and expressed using numbers. Qualitative data is descriptive and conceptual.
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A binary compound of boron and hydrogen has the following percentage composition: 78.14% boron, 21.86% hydrogen. If the molar ma
algol [13]

Answer:

Empirical formula: BH3

Molecular Formula: B2H6

Explanation:

To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:

100% _____ 27 g

78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron

100% ______27 g

21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen

100% _____ 28 g

78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron

100% _____ 28g

21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen

So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.

The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.

The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.

8 0
3 years ago
A 28-kg child can consume a maximum of 23 children's acetaminophen tablets in an 8-h period without exceeding the safety-limit m
Nesterboy [21]

Answer:

(b)90mg/lb

Explanation:

The child can consume a maximum of 23 tablets with 80mg of acetaminophen, the total acetaminophen ingest is:

23*80=1840mg

This value is for 8 hours, 8 hours is 1/3 of one day. This means that the dose that can be consumed in 24 hours is 3 times 1840mg.

1840*3=5520mg

To obtain the maximum allowable dose in mg per pound of body weight, divide this last value by the weight of the child in pounds.

Conversion of units: 28Kg(\frac{2.20lb}{1Kg} )=61.6lb

\frac{5520}{61.6} =89.61\approx90mg/lb

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Answer:

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