Answer:
18 boys
Step-by-step explanation:
boys/girls = 3/11 = b/66
3/11 = b/66
11b = 3 × 66
b = 3 × 6
b = 18
There are 18 boys.
Probability between z = 0 and z = 3.01 is given by
P(0<z<3.01) = P(z<3.01) - P(z<0)
Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987
Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987
Answer:
Step-by-step explanation:
Let older brother age be x and the age difference between the brothers be y
Younger brother's current age = x - y
When older brother's age was at x - y, younger brother's age was x - 2y = 2
When young brother's age will be at x, older brother's age will be x + y = 20
Subtracting the first equation from the second: 3y = 18
y = 6
x = 14
So the older brother is 14 and the younger brother is 8.
Sum of three son's ages now = 15 + 11 + 7 = 33
Daddy's age now = 45
Age difference = 12
Each year, daddy's age goes up by 1 while the sum of three son's ages goes up by 3.
Dividing the age difference by the difference in age gain, 12 / (3 -1) = 12 / 2
= 6
So in 6 years when daddy is 51 and the sum of sons at 21, 17 and 13 will be equal.
Answer:
x=16
Step-by-step explanation:
Hope this helps