KE = 1/2 * m * v^2
KE = 1/2 * 0.135 * 40^2
KE = 1/2 * 0.135 * 1600
KE = 108 J
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The drastic increase in the emission of CO2 (carbon dioxide)
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the change of temperature in the atmosphere (click the following link for a
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effects of </span>global warming).
The correct answer between all
the choices given is the last choice or letter D. I am hoping that this answer
has satisfied your query and it will be able to help you in your endeavor, and
if you would like, feel free to ask another question.
Answer:
The space cadet that weighs 800 N on Earth will weigh 1,600 N on the exoplanet
Explanation:
The given parameters are;
The mass of the exoplanet = 1/2×The mass of the Earth, M = 1/2 × M
The radius of the exoplanet = 50% of the radius of the Earth = 1/2 × The Earth's radius, R = 50/100 × R = 1/2 × R
The weight of the cadet on Earth = 800 N

Therefore, for the weight of the cadet on the exoplanet, W₁, we have;

The weight of a space cadet on the exoplanet, that weighs 800 N on Earth = 1,600 N.
Answer:
The correct answer is "4.26 m".
Explanation:
Given:
Wavelength,

or,

Distance,

or,

Distance between the 1st and 2nd dark fringes,
As we know,
⇒ 
or,
⇒ 
By substituting the values, we get




Answer:
Explanation:
4.95s≈5s
Use equation :
h=G*t²/2
h=120m ----hight of cliff
G=9.81m/s²
t=?
-----------------------
h=G*t²/2
120m=9.81m/s²*t²/2
240m=9.81m/s²*t²
t²=240m/ 9.81m/s²
t²=24.46s
t=√24.46s²
t=4.95 s≈5s