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tester [92]
3 years ago
12

"The work done on an ideal gas system in an isothermal process is -400 J. What is the change in internal (thermal) energy of the

gas?"
Physics
1 answer:
Archy [21]3 years ago
6 0

Answer:

zero

Explanation:

Work done = - 400 J

In an isothermal process, the temperature remains constant. So, according to the first law of thermodynamics

dQ = dU + dW

As the temperature remains constant and the change in internal energy is the function of change in temperature, here change is temperature is zero so the change in internal energy is also zero.

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3 years ago
A 3.0 m tall, 40 cm diameter concrete column supports a 235,000 kg load. by how much is the column compressed? assume young's mo
statuscvo [17]
The Young modulus E is given by:
E= \frac{F L_0}{A \Delta L}
where 
F is the force applied
A is the cross-sectional area perpendicular to the force applied
L_0 is the initial length of the object
\Delta L is the increase (or decrease) in length of the object.

In our problem, L_0 = 3.0 m is the initial length of the column, E=3.0 \cdot 10^{10}N/m^2 is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:
r= \frac{d}{2}= \frac{40 cm}{2}=20 cm=0.2 m
and the cross-sectional area is
A=\pi r^2 = \pi (0.20 m)^2=0.126 m^2
The force applied to the column is the weight of the load:
W=mg=(235000 kg)(9.81 m/s^2)=2.305 \cdot 10^6 N

Now we have everything to calculate the compression of the column:
\Delta L =  \frac{F L_0}{EA}= \frac{(2.305\cdot 10^6 N)(3.0 m)}{(3.0\cdot 10^{10}N/m^2)(0.126 m^2)} =1.83\cdot 10^{-3}m
So, the column compresses by 1.83 millimeters.
3 0
3 years ago
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