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Yakvenalex [24]
3 years ago
15

Consider two liquids, labeled A and B, that are both pure substances. Liquid A has

Chemistry
1 answer:
Scrat [10]3 years ago
4 0
E is the correct answer
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Absolute zero is
Dmitrij [34]

Answer:

The coldest temperature possible

Explanation:

        Absolute zero =      0 K

A. is wrong.      0 °C = 273 K

B. is wrong. -210 °C =   63 K

C. is wrong.    32 °F = 273 K

E. is wrong.  -196°C =    77 K

5 0
3 years ago
2. Have someone hold the mirror for you, slowly move at least 3 m away from the it.
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Answer: Slowly move at least 3 m away from the side mirror. Observe your image as you ... Compare the images formed in different mirrors. ... but if i stand 3m away, even though there is no light, it reflects the other material it can ... is transparent so you cannot see yourself much in the mirror, that is my observation.

Explanation:

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3 years ago
What is the hydridization of TeBr4
Debora [2.8K]
It's sp3d according to the lewis dot structure (four bonds, one lone pair).
5 0
3 years ago
A part of the periodic table is shown below:
mylen [45]
I think is oxygen that what i think
8 0
3 years ago
Read 2 more answers
In the redox conversion of Ni2+ to NiO4−, the oxidation number of Ni goes from (−2, 0, +2) to (−1, +1, +7, +9). Recall that the
inessss [21]
Oxidation number of an atom is the charge that atom would have if the compound is composed of ions. In neutral substances that contains atoms of one element the oxidation number of an atom is zero. Thus atoms in O2, Ni2, and aluminium all have oxidation number of zero.
In this case, Ni2, the oxidation number of Ni atom is zero, 
for NiO4-, assuming oxidation number of Ni is x 
 (x ×1) + (-2 × 4) = -1
  x = + 7
Therefore, the oxidation number goes from 0 to +7
7 0
4 years ago
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