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qwelly [4]
3 years ago
7

Write the electron configuration for the element titanium, TiTi. Express your answer in order of increasing orbital energy as a

string without blank space between orbitals. For example, the electron configuration of LiLi could be entered as 1s^22s^1 or [He]2s^1.
Chemistry
1 answer:
Julli [10]3 years ago
3 0

Answer:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d² or [Ar] 3d² 4s²

Explanation:

Electron configuration can basically be referred to as the location of electron; how the electrons are arranged in the orbitals of the atoms.

Following Aufbau principle, electrons are arranged in the following order of orbitals.

1s 2s 2p 3s 3p 4s 3d and so on.

The s can hold a maximum of 2 electrons, p can hold a maximum of 6 electrons and d can hold a maximum of 10 electrons.

Titanium has an atomic number of 22. So the arrangement is given as;

Ti = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d²

The short hand notation is given as;

[Ar] 3d² 4s²

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<h2>B)</h2>

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\text{Let}\\\\x-\text{a volume of}\ 20\%\ \text{saline solution}\\\\y-\text{a volume of }\ 50\%\ \text{saline solution}\\\\p\%=\dfrac{p}{100}\\\\20\%=\dfrac{20}{100}=\dfrac{2}{10}=0.2\\\\50\%=\dfrac{50}{100}=\dfrac{5}{10}=0.5\\\\0.2x-\text{a volume of salt in }\ 20\%\ \text{saline solution}\\0.5y-\text{a volume of salt in }\ 50\%\ \text{saline solution}\\\\60mL-\text{a volume of}\ 28\%\ \text{saline solution}\\\\28\%=\dfrac{28}{100}=0.28

0.28\cdot60mL=16.8mL-\text{a volume of salt in }\ 28\%\ \text{saline solution}\\\\\text{Equations}\\\\(1)\qquad x+y=60\\(2)\qquad0.2x+0.5y=16.8

\left\{\begin{array}{ccc}x+y=60\\0.2x+0.5y=168&\text{multiply both sides by 10}\end{array}\right\\\left\{\begin{array}{ccc}x+y=60&\text{multiply both sides by (-2)}\\2x+5y=168}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-2x-2y=-120\\2x+5y=168}\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad3y=48\qquad\text{divide both sides by 3}\\.\qquad y=16

\text{Put the value of}\ y\ \text{to the first equation:}\\\\x+16=60\qquad\text{subtract 16 from both sides}\\x=44

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