Answer:
d
Explanation:
because nuclear charge ( no. of protons) increases
The answer is: [D]: " 417 cm³ " .
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Explanation: Use the formula:
V₁ /T₁= V₂ /T₂ ;
in which: V₁ = initial volume = 556 cm³ ;
T₁ = initial temperature = 278 K ;
V₂ = final ("new") temperature = 308 K
T₂ = final ("new:) volume = ?
Solve for "V₂" ;
Since: V₁ /T₁= V₂ /T₂ ;
We can rearrange this "equation/formula" to isolate "V₂" on one side of the equation; and then we can plug in our know values to solve for "V₂" ;
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V₁ /T₁= V₂ /T₂ ; Multiply EACH side of the equation by "T₂ " :
→ T₂ (V₁ /T₁) = T₂ (V₂ /T₂) ;
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to get:
↔ T₂ (V₂ /T₂) = T₂ (V₁ /T₁) ;
→ V₂ = T₂ (V₁ /T₁) ;
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Now, plug in our known values, to solve for "V₂" ;
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→ V₂ = T₂ (V₁ /T₁) ;
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→ V₂ = 308 K ( 556 cm³ /278 K) ;
→ The units of "K" cancel to "1" ; and we have:
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→ V₂ = 308*( 556 cm³ / 278 ) = [(208 * 556) / 278 ] cm³ ;
Note: We will keep the units of volume as: "cm³ "; since all the answer choices given are in units of: "cm³ " ; {that is, "cubic centimeters"}.
→ [(208 * 556) / 278 ] cm³ = [ (115,648) / (278) ] cm³ ;
→ For the "(115,648)" ; round to "3 (three significant figures)" ;
→ "(115,648)" → rounds to: "116,000" ;
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→ (116,000) / (278) = 417.2661870503597122 ;
→ round to 3 significant figures; → "417 cm³ " ;
→ which corresponds with "choice [D]".
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The answer is: [D]: "417 cm³ " .
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Answer: static electricity
Explanation:
Answer:
0.7246 M
Explanation:
Considering:
Or,
Given :
For 
:
Molarity = 2.086 M
Volume = 188.9 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 188.9×10⁻³ L
Thus, moles of :
Moles of = 0.39405 moles
For NaOH :
Molarity = 0.4607 M
Volume = 269.3 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 269.3×10⁻³ L
Thus, moles of NaOH :
Moles of NaOH = 0.1241 moles
According to the given reaction:
1 moles of react with 2 moles of NaOH to form 1 mole of sodium sulfate.
Thus,
2 moles of NaOH react with 1 mole of
1 mole of NaOH react with 1/2 mole of
0.1241 moles of NaOH react with (1/2)×0.1241 mole of
Moles of that got reacted = 0.06205 moles
Unreacted moles = Total moles - Moles that got reacted = 0.39405 - 0.06205 moles = 0.332 moles
Total volume = 188.9×10⁻³ L + 269.3×10⁻³ L = 458.2×10⁻³ L
Concentration of :
<u>Concentration of = 0.7246 M</u>
Answer:
percentage composition of O in HClO IS 30.47
Explanation:
percentage composition of oxygen in HClO =(atomic mass of O)/(atomic mass of HClO)×100
=
=30.47
