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Fofino [41]
3 years ago
8

Which factors will result in a stronger ionic bond overall?a. larger ions b. similarity of ionic sizes c. greater absolute charg

es d. smaller ions
Chemistry
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

c. greater absolute charges

d. smaller ions

Explanation:

An<em> </em><em>ionic bond</em><em> is an electrostatic force that holds ions together in an ionic compound</em>. The overall stability of a solid ionic compound depends on the interactions of all the ions and not merely on the interaction of a single cation with a single anion. A quantitative measure of the stability of any ionic solid is its <em>lattice energy</em><em>, defined as the energy required to completely separate one mole of a solid ionic compound into gaseous ions.</em>

Lattice energy cannot be measured directly. However, if we know the structure and composition of an ionic compound, we can calculate the compound’s lattice energy by using <em>Coulomb’s law</em><em>, which states that the potential energy (</em><em>E</em><em>) between two ions is directly proportional to the product of their charges and inversely proportional to the distance of separation between them</em>. For a single Li⁺ ion and a single F⁻ ion separated by distance r, the potential energy of the system is given by:

E = k × (Q Li⁺ Q F⁻) ÷ r

where QLi⁺and QF⁻ are the charges on the Li⁺ and F⁻ ions and k is the proportionality  constant. From this equation we can see that the greater the absolute charges and the smaller the ions (smaller r) the greater the potential energy E, which means that the ionic bond will be stronger.

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PLS HELP-CHEMISTRY: What is the molar concentration of an ammonia solution in which there are 0.1557 grams
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Answer: M = 0.036 M

Explanation: Solution attached:

First convert mass of NH3 to moles

Next convert volume in mL to L

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M = n / L

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Which best describes the trends in electronegativity on the periodic table?
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WILL MARK BRANILEST
ahrayia [7]

Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

4 0
4 years ago
How many moles of S would I have if I had 11 grams? (Stoichiometry) HELP
zepelin [54]
<h3>Answer:</h3>

0.34 mol S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

11 g S

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 11 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})
  2. Multiply/Divide:                  \displaystyle 0.343 \ mol \ S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

0.343 mol S ≈ 0.34 mol S

4 0
3 years ago
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