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Fofino [41]
3 years ago
8

Which factors will result in a stronger ionic bond overall?a. larger ions b. similarity of ionic sizes c. greater absolute charg

es d. smaller ions
Chemistry
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

c. greater absolute charges

d. smaller ions

Explanation:

An<em> </em><em>ionic bond</em><em> is an electrostatic force that holds ions together in an ionic compound</em>. The overall stability of a solid ionic compound depends on the interactions of all the ions and not merely on the interaction of a single cation with a single anion. A quantitative measure of the stability of any ionic solid is its <em>lattice energy</em><em>, defined as the energy required to completely separate one mole of a solid ionic compound into gaseous ions.</em>

Lattice energy cannot be measured directly. However, if we know the structure and composition of an ionic compound, we can calculate the compound’s lattice energy by using <em>Coulomb’s law</em><em>, which states that the potential energy (</em><em>E</em><em>) between two ions is directly proportional to the product of their charges and inversely proportional to the distance of separation between them</em>. For a single Li⁺ ion and a single F⁻ ion separated by distance r, the potential energy of the system is given by:

E = k × (Q Li⁺ Q F⁻) ÷ r

where QLi⁺and QF⁻ are the charges on the Li⁺ and F⁻ ions and k is the proportionality  constant. From this equation we can see that the greater the absolute charges and the smaller the ions (smaller r) the greater the potential energy E, which means that the ionic bond will be stronger.

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Answer:

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Explanation:

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3 years ago
A gas has a volume of 5.00 L at 0°C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to ea
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Answer:

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C  (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume =  87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

2)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

3)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

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