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77julia77 [94]
3 years ago
8

Roberto will save 1/6 of his allowance each day. If he gets $2.00 a day, about how much money will he save each day

Mathematics
1 answer:
slamgirl [31]3 years ago
3 0
I hope you can read cursive and I hope this helps!

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2 divided by 3.4 divided by 5
Grace [21]

2/3.4/5

=0.1176

that is the answer

4 0
3 years ago
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Find the equation of the line in slope-intercept form.Slope is 2/3 through (3, 4)
Elena-2011 [213]

Remark

You have been told that the slope of the line is 2/3. That means that if the general equation is y = mx + b is the equation for the slope intercept formula and since m = the slope, then m also equals 2/3

y = (2/3)x + b

Use the point to find b

when x = 3

y = 4                       This comes from the point

4 = (2/3) * 3 + b      multiply 2/3 and 3 together

4 = 6/3 + b             Simplify 6/3

4 = 2 + b                  Subtract 2 from both sides

4 - 2 = b                   Combine

2 =  b              

Equation

y = (2/3)x + 2

8 0
3 years ago
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a design a rectangular patio the patio has an area of 432 square feet.The width of the patio is 3/4 it's length.What is the leng
Sloan [31]
The answer is 108 cause you do 4/4-3/4 which 1/4 and then you will do 1/4 of 432 which is 108

6 0
3 years ago
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Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal. (Enter your answers as a comma-separated list.)
Gala2k [10]

Answer:

The values of x that makes these vectors orthogonal are x = 2 and x = 4.

Step-by-step explanation:

Orthogonal vectors

Suppose we have two vectors:

v_{1} = (a,b,c)

v_{2} = (d,e,f)

Their dot product is:

(a,b,c).(d,e,f) = ad + be + cf

They are ortogonal is their dot product is 0.

Solving quadratic equations:

To solve this problem, we are going to need tosolve a quadratic equation.

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4a

Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal.

(4,x,-6)(2,x,x) = 8 + x^{2} - 6x

These vectors are going to be orthogonal if:

x^{2} -6x + 8 = 0

This is a quadratic equation, in which a = 1, b = -6, c = 8. So

\bigtriangleup = 6^{2} - 4*1*8 = 4

x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

The values of x that makes these vectors orthogonal are x = 2 and x = 4.

3 0
3 years ago
Martin was making play dough. He added 3/4 cup of flour to the bowl. Then he added another 3/8 cup. Is the total amount of flour
Sergio039 [100]

Answer:

It's greater then one cup

Step-by-step explanation:

Hope it helps :)

Have a good day/night

Brainliest pls?

6 0
3 years ago
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