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Olenka [21]
3 years ago
10

If you are looking for a material that is a good conductor, you will look for a material that will

Physics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0
You will look for a material that will allow heat energy to move freely among particles; materials like copper or aluminum.
schepotkina [342]3 years ago
3 0
A material with lots of free electrons. 
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Reil [10]

Mass of oxygen stays the same.

8 0
3 years ago
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A 54.0-kg projectile is fired at an angle of 30.0° above the horizontal with an initial speed of 126 m/s from the top of a cliff
Nikolay [14]

Answer:

a) The initial total mechanical energy of the projectile is 498556.296 joules.

b) The work done on the projectile by air friction is 125960.4 joules.

c) The speed of the projectile immediately before it hits the ground is approximately 82.475 meters per second.

Explanation:

a) The system Earth-projectile is represented by the Principle of Energy Conservation, the initial total mechanical energy (E) of the project is equal to the sum of gravitational potential energy (U_{g}) and translational kinetic energy (K), all measured in joules:

E = U_{g} + K (Eq. 1)

We expand this expression by using the definitions of gravitational potential energy and translational kinetic energy:

E = m\cdot g\cdot y + \frac{1}{2}\cdot m\cdot v^{2} (Eq. 1b)

Where:

m - Mass of the projectile, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

y - Initial height of the projectile above ground, measured in meters.

v - Initial speed of the projectile, measured in meters per second.

If we know that m = 54\,kg, g = 9.807\,\frac{m}{s^{2}}, y = 132\,m and v = 126\,\frac{m}{s}, the initial mechanical energy of the earth-projectile system is:

E = (54\,kg)\cdot \left(9.807\,\frac{m}{s^{2}}\right)\cdot (132\,m)+\frac{1}{2}\cdot (54\,kg)\cdot \left(126\,\frac{m}{s} \right)^{2}

E = 498556.296\,J

The initial total mechanical energy of the projectile is 498556.296 joules.

b) According to this statement, air friction diminishes the total mechanical energy of the projectile by the Work-Energy Theorem. That is:

W_{loss} = E_{o}-E_{1} (Eq. 2)

Where:

E_{o} - Initial total mechanical energy, measured in joules.

E_{1} - FInal total mechanical energy, measured in joules.

W_{loss} - Work losses due to air friction, measured in joules.

We expand this expression by using the definitions of gravitational potential energy and translational kinetic energy:

W_{loss} = E_{o}-K_{1}-U_{g,1}

W_{loss} = E_{o} -\frac{1}{2}\cdot m\cdot v_{1}^{2}-m\cdot g\cdot y_{1} (Eq. 2b)

Where:

m - Mass of the projectile, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

y_{1} - Maximum height of the projectile above ground, measured in meters.

v_{1} - Current speed of the projectile, measured in meters per second.

If we know that E_{o} = 498556.296\,J, m = 54\,kg, g = 9.807\,\frac{m}{s^{2}}, y_{1} = 297\,m and v_{1} = 89.3\,\frac{m}{s}, the work losses due to air friction are:

W_{loss} = 498556.296\,J -\frac{1}{2}\cdot (54\,kg)\cdot \left(89.3\,\frac{m}{s} \right)^{2} -(54\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (297\,m)

W_{loss} = 125960.4\,J

The work done on the projectile by air friction is 125960.4 joules.

c) From the Principle of Energy Conservation and Work-Energy Theorem, we construct the following model to calculate speed of the projectile before it hits the ground:

E_{1} = U_{g,2}+K_{2}+1.5\cdot W_{loss} (Eq. 3)

K_{2} = E_{1}-U_{g,2}-1.5\cdot W_{loss}

Where:

E_{1} - Total mechanical energy of the projectile at maximum height, measured in joules.

U_{g,2} - Potential gravitational energy of the projectile, measured in joules.

K_{2} - Kinetic energy of the projectile, measured in joules.

W_{loss} - Work losses due to air friction during the upward movement, measured in joules.

We expand this expression by using the definitions of gravitational potential energy and translational kinetic energy:

\frac{1}{2}\cdot m \cdot v_{2}^{2} = E_{1}-m\cdot g\cdot y_{2}-1.5\cdot W_{loss} (Eq. 3b)

m\cdot v_{2}^{2} = 2\cdot E_{1}-2\cdot m \cdot g \cdot y_{2}-3\cdot W_{loss}

v_{2}^{2} = 2\cdot \frac{E_{1}}{m}-2\cdot g\cdot y_{2}-3\cdot \frac{W_{loss}}{m}

v_{2} = \sqrt{2\cdot \frac{E_{1}}{m}-2\cdot g\cdot y_{2}-3\cdot \frac{W_{loss}}{m}  }

If we know that E_{1} = 372595.896\,J, m = 54\,kg, g = 9.807\,\frac{m}{s^{2}}, y_{2} =0\,m and W_{loss} = 125960.4\,J, the final speed of the projectile is:

v_{2} =\sqrt{2\cdot \left(\frac{372595.896\,J}{54\,kg}\right)-2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0\,m)-3\cdot \left(\frac{125960.4\,J}{54\,kg}\right)  }

v_{2} \approx 82.475\,\frac{m}{s}

The speed of the projectile immediately before it hits the ground is approximately 82.475 meters per second.

7 0
3 years ago
Which is the balanced chemical equation representing the decomposition of hydrogen peroxide? H2O2 H2O + O2
Bess [88]
2H2O2 ------> 2H2O +O2

because we're given one side with 2 hydrogens and 2 oxygens and another sie with  3 oxygens and 2 hydrogens. The hydrogens are balanced but the oxygens are not. You can't make the oxygen a three on the reactants side with a whole number so you multiply by 2. 

Now you have 4 hydrogens and 4 oxygens on one side and 4 hydrogens and 4 oxygens on the other :)
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3 years ago
LAST ONE! ASAP PLEASE
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Answer:

There are so many questions which one you don't know

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Come up with your own team sports game and make your own rules and regulation.​
bezimeni [28]

SO my sports name would be called " Basvollball" It's where you have to hit in a volleyball into a basketball hoop, of course, the time is the same as football with increments of 5 minutes for junior high and 7 minutes for high school with halftime. Also, the ball can never touch the ground and if the ball ever hits the floor its the other's team ball. To decide which team gets the ball, a coin flip will decide it. For the point system, it depends on how far the ball is hit from so it's like basketball from 3 pointers to 2 points inside the line. If the team ever reaches 30 points without the other team scoring, the team who's winning will automatically win after the time runs out in that period or quarter. You can use every body part, as long as, the ball doesn't touch the floor, and you can only use your body to push someone, no pushing with hands or arms. You can play this sport indoors or outside whether the team has a field available. There's also a maximum of 14 players on the field, so 7 players on each team.

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