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3 years ago

How to turn 258 out of 300 into a decimal and as a percent

2 answers:

8 0

258/300 u have to simplify 300 and 258 r both divisible by 3, 258/300 divided by 3/3 equals 86/100, as a decimal this is 0.86 and as a percent is is 86%

hichkok12 [17]3 years ago

3 0

Decimal: Convert the fraction by dividing the numerator by the denominator

Answer: 0.86

Percentage: Convert the fraction to a decimal, then multiply by 100

Answer: 86%

You might be interested in

The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the

SVEN [57.7K]

Given,
The sum of three integers is 92

So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"

Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)

Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,

x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17

Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51

Now,
Substituting the value of "x" in equation (2),

z = 2 (17 ) - 10
z = 34 - 10
z = 24

So, the numbers are 17, 51 and 24

NEVER HATE MATH!!!

3 0

3 years ago

Point C is on line segment \overline{BD} BD . Given CD=x,CD=x, BC=5x-5,BC=5x−5, and BD=2x+7,BD=2x+7, determine the numerical len

NARA [144]

Answer:

$CD = 3$

Step-by-step explanation:

Given

$CD = x$

$BC = 5x - 5$

$BD = 2x + 7$

Required

Determine CD

Since, C is a point on BD, the relationship between the given parameters is;

$BD = BC + CD$

Substitute the values of BD, BC and CD

$2x + 7 = 5x - 5 + x$

Collect Like Terms

$2x - 5x - x = -5 - 7$

$-4x = -12$

Divide both sides by -4

$\frac{-4x}{-4} = \frac{-12}{-4}$

$x = 3$

To determine the length of CD;

Substitute 3 for x in $CD = x$

Hence;

$CD = 3$

3 0

3 years ago

which of the following properties could be used to rewrite the expression (2/3•1/5)•5/2 as 2/3•(5/2•(5/2•1/5) sorry to ask Su ma

slamgirl [31]

The original expression is given by:
$( \frac{2}{3}*\frac{1}{5})*\frac{5}{2}$
The correct way to rewrite the expression is given by:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})
$
For this, we use two properties:

Associative property:
The way of grouping the factors does not change the result of the multiplication:
$\frac{2}{3}*(\frac{1}{5}*\frac{5}{2})$

Commutative property:
The order of the factors does not vary the product:
$\frac{2}{3}*(\frac{5}{2}*\frac{1}{5})$

8 0

3 years ago

The function y = x2 is transformed to y = (x + 4)2. Which statement is true about the transformed function? It is an even functi

xxMikexx [17]

Even function: f(-x) = f(x). If you replace x by -x you should find the same function.
Odd function: f(-x) = -f(x). If you replace x by -x you find the same function with opposite sign;
Is f(-x) = f(x)?
f(x) = (x+4)² = x² + 8x +16
f(-x) = (-x+4)² = x² - 8x + 16, then it's not an even function

Is f(-x) = -f(x)?
f(-x) = (-x+4)² = x² + 8x + 16 , then it's not an odd function
It is neither an even nor an odd function

7 0

3 years ago

Write the equation for an absolute value function with the following transformations:

Kipish [7]

Answer:

j(x) = 5 |x+9|-23

Step-by-step explanation:

f(x) = |x|

translate left 9 units

y = f(x + C) C > 0 moves it left

g(x) = |x+9|

translate down 23 units

y = f(x) + C C < 0 moves it down

h(x)= |x+9|-23

stretch by a factor of 5

y = Cf(x) C > 1 stretches it in the y-direction

j(x) = 5 |x+9|-23

5 0

3 years ago