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3 years ago

What percent of the people chose turkey or ham as their favorite sandwich? A. 6% B. 50% C. 28% D. 62%

Mathematics

1 answer:

Elenna [48]3 years ago

7 0

B IS THE CORRECT ANSWER
BTWWW

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HELP NEED HELP FAST ANSWER FAST PLEZ

vodomira [7]

Answer

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3 years ago

Triangles ABC and ADC are shown below. Paul claims that triangles ABC and ADC are congruent.

guapka [62]

Answer:

1 no

2 yes

3 no

4 yes

5 no

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3 years ago

Read 2 more answers

The equation y ̂=844.697x^2+3723.485x-13,650 models the annual profits of a new business, where x is the number of years since t

julsineya [31]

The answer is $37,923

<span>y = 844.697x^2 + 3723.485x - 13,650
x - number of years
y - the annual profit

If x = 8, the annual profit y is:
y = </span>844.697 * 8^2 + 3723.485 * 8 - 13,650
y = 844.697 * 64 + 29,787.88 - 13,650
y = 54,060.608 + 16,137.88
y = 37,922.728 ≈ 37,923

5 0

4 years ago

Find the mean, median and mode from the chart below

BlackZzzverrR [31]

Answer:

1. mean=1.5, median=1.7, mode is 1.8

2. mean=102,median=134, mode=no mode

3. mean=1885,median=2300, mode=2300

Step-by-step explanation:

6 0

3 years ago

12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$