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Anastaziya [24]
3 years ago
13

In the circuit described by the diagram, which pair of resistors is connected in parallel?

Physics
1 answer:
scoundrel [369]3 years ago
6 0

Option 4 ( R2 and R3 ) is the correct answer.

Explanation:

  • In the below given diagram, we can see a circuit diagram that has four resistors such as R1, R2, R3, and R4.
  • The opening of the circuit is noted as "a" and the ending is noted as "b".
  • By observing the above diagram, we can clearly see that R2 and R3 are the pair of resistors that are connected in a parallel manner.
  • Where all the other resistors such as R1 and R4 are neither connected in parallel nor in series.

Hence we can conclude that Resistor R2 and R3 are the ones that are connected in parallel.

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Show solution for # 4
velikii [3]
M1 = 750Kg, v1 = 10m/s
m2 = 2500Kg , v2= 0 (because in problem say cuz that object don t move).

The momentum before colision is equal with the momentum after colision:

m1v1 + m2v2 = (m1+m2)v3 => v3 is the velocity after colison and that s u want to caluclate for your problem

=> m1v1 = (m1+m2)v3 => v3 = m1v1/(m1+m2) now u should do the math i think v3 prox 2,4 but not sure u should caculate
7 0
3 years ago
A long, straight metal rod has a radius of 5.75 cm and a charge per unit length of 33.3 nC/m. Find the electric field at the fol
PIT_PIT [208]

Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a)  at 4.75 cm

b)  at 20.5 cm

c) at 125.0 cm

Given that:

the charge (q) = 33.3 nC/m

= 33.3 × 10⁻⁹ c/m

radius of rod = 5.75 cm

a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

Then, the electric field will be zero.

b) The electric field formula E = \dfrac{kq }{d}

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}

E = 1461.95 N/C

c) The electric field E is calculated as:

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

E = 239.76 N/C

7 0
3 years ago
When a current of 0.015 A passes through human body at 240 volts p.d it<br><br>causes​
geniusboy [140]

Explanation:

Given that,

Current, I = 0.015 A

Voltage, V = 240 volts

We need to find the resistance. Using Ohm's law we can find it as follows :

V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{240}{0.015}\\\\R=16000\ \Omega

So, When a current of 0.015 A passes through human body at 240 volts p.d it  causes​  16000 ohms of resistance.

3 0
3 years ago
What happens when red, blue, and green light come together?
Alja [10]

Answer:

I believe if red, blue, and green light come together it would produce White light.

8 0
2 years ago
Read 2 more answers
Dams hold collected water back from flowing at their normal rate. What type of energy is in the collected water above the dam? c
Andreyy89
It would be mechanical potential energy.
8 0
3 years ago
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