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3 years ago

PLS HELP ASAP!

Physics

1 answer:

Oduvanchick [21]3 years ago

4 0

2.09sec

Add them together then divide by three because there are three numbers

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Earth's distance from the sun it effects every living being on the Earth.

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3 years ago

(a) A runaway train car that has a mass of 14000 kg travels at a speed of 7.5 m/s down a track. Compute the time (in seconds) re

Sauron [17]

Answer:

In the picture.

Explanation:

I hope that it's a clear solution and explanation.

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3 years ago

Read 2 more answers

An egg is dropped from a third-floor window and lands on a foam-rubber pad without breaking. The acceleration of gravity is 9.81

Katena32 [7]

Answer:

The pad compresses for about 5 cm.

Explanation:

Given:

- The mass of the egg m = 56.4 g

- The height at which egg drops h = 14.0 m

- The total thickness of foam d = 7.85 cm

- Total time taken to stop the egg t = 6.05 ms

Find:

By how much is the pad compressed? s

Solution:

- Apply conservation of energy from release point to point just before egg contacts the pad. To compute the speed of egg at impact

ΔP.E = ΔK.E

m*g*( h - t ) = 0.5*m*v^2

v = sqrt( 2*g*( h - d ) )

v = sqrt ( 2*9.81*(14 - 0.0785))

v = 16.53 m/s

- Now to determine the the acceleration (Assuming constant ) at which pad compresses we will use first equation of motion till the point the final velocity is zero.

vf = vi + a*t

0 = 16.53+ a*(0.00605)

a = 16.53 / 0.00605

a = -2731.73 m/s^2

- To determine the total amount of pad compressed (s), we will use the third equation of motion as follows:

vf^2 = vi^2 + 2*a*s

0 = 16.53^2 + 2*(-2731.73)*s

s = 16.53^2 / (2*2731.73)

s = 0.05 m = 5 cm

- The pad compresses for about 5 cm.

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3 years ago

A wagon is pulled along level ground by exerting a force of 26 26 pounds on a handle that makes an angle of 30 degrees 30° with

yawa3891 [41]

Work is calculated by multiplying the force exerted with the distance covered by the object. The force and the displacement should be parallel. In this item, we have to calculate first the horizontal component of force.
x-component of force = (26 lbs)(cos 30°)
= 22.52 lbs
Multiplying the calculated value by the displacement of 90 ft will give us the final answer of 2026.50 lb.ft.

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3 years ago

A cockroach of mass m lies on the rim of a uniform disk of mass 5m that can rotate freely about its center like a merry-go-round

Tatiana [17]

Given data:

The mass of cockroch is m.

The mass of disk is 5m.

The initial speed of cockroch and disk is ω=0.26 rad/s.

Considering the radius of the disk is r, then the halfway radius of the disk will be r/2.

Part (a)

The final angular velocity can be calculated as,

$\begin{gathered} (I+I)\omega=(I+I)_{final}\omega^{\prime} \\ (mr^2+\frac{1}{2}5mr^2)0.26=(m(\frac{r}{2})^2+\frac{1}{2}5m(\frac{r}{2})^2)\omega^{\prime} \\ 0.91=0.875\omega^{\prime} \\ \omega^{\prime}=1.04\text{ rad/s} \end{gathered}$

Thus, the final speed is 1.04 rad/s.

Part (b)

The ratio of kinetic energy can be calculated as,

$\begin{gathered} \frac{K_f}{K_i}=\frac{\frac{1}{2}(I+I)_{final}\omega^2}{\frac{1}{2}(I+I)\omega^2} \\ \frac{K_f}{K_i}=\frac{\frac{1}{2}(m(\frac{r}{2})^2+\frac{1}{2}5m(\frac{r}{2})^2_{})(1.04)^2}{\frac{1}{2}(mr^2+\frac{1}{2}5mr^2)(0.26)^2} \\ \frac{K_f}{K_i}=7.42 \end{gathered}$

Thus, the ratio of kinetic energy is 7.42.

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1 year ago