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Mashcka [7]
3 years ago
7

PLS HELP ASAP!

Physics
1 answer:
Oduvanchick [21]3 years ago
4 0

2.09sec

Add them together then divide by three because there are three numbers

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Examples were friction is not useful
expeople1 [14]
The old electricity meters with disk using sapphire bearings for friction to be minimal to not aggravate metering
7 0
3 years ago
Light from the sun reaches the earth in 8.3 minutes. the speed of light is 3.0  108 m/s. in kilometers, how far is the earth fr
Flura [38]
To determine the distance of the light that has traveled given the time it takes to travel that distance, we need a relation that would relate time with distance. In any case, it would be the speed of the motion or specifically the speed of light that is travelling which is given as 3x10^8 meters per second. So, we simply multiply the time to the speed. Before doing so, we need to remember that the units should be homogeneous. We do as follows:

distance = 3x10^8 m/s ( 8.3 min ) ( 60 s / 1 min ) = 1.494x10^11 m

Since we are asked for the distance to be in kilometers, we convert

distance = 1.494x10^11 m ( 1 km / 1000 m) = 149400000 km
6 0
3 years ago
A clothes dryer in a home draws a current of 10 amps when connected on a special 220-volts household circuit.what is the resista
aliya0001 [1]

Answer:

22Ω

Explanation:

if    V ⇒ voltage

      I ⇒ current

      R ⇒ resistance

V = IR

220 = 10 x R

220 / 10 = R

22 = R

8 0
2 years ago
What displacement in cm would occur with a 75 N/m spring if you placed a 300 N weight on the spring?
ollegr [7]

Surface tension=75N/m

Weight=300N

\\ \bull\tt\longmapsto Surface\:Tension=\dfrac{Weight}{Displacement}

\\ \bull\tt\longmapsto Displacement=\dfrac{Weight}{Surface\:Tension}

\\ \bull\tt\longmapsto Displacement=\dfrac{300}{75}

\\ \bull\tt\longmapsto Displacement=4m

\\ \bull\tt\longmapsto Displacement=400cm

6 0
2 years ago
A 10.0-kg box starts at rest on a level floor. An external, horizontal force of 2.00 × 102 N is applied to the box for a distanc
Harman [31]

Answer:

vf = 11.2 m/s

Explanation:

m = 10 Kg

F = 2*10² N

x = 4.00 m

μ = 0.44

vi = 0 m/s

vf = ?

We can apply Newton's 2nd Law

∑ Fx = m*a   (→)

F - Ffriction = m*a  ⇒  F - (μ*N) = F - (μ*m*g) = m*a   ⇒  a = (F - μ*m*g)/m

⇒    a = (2*10² N - 0.44*10 Kg*9.81 m/s²)/10 Kg = 15.6836 m/s²

then , we use the equation

vf² = vi² + 2*a*x    ⇒    vf = √(vi² + 2*a*x)

⇒   vf = √((0)² + 2*(15.6836 m/s²)*(4.00m)) = 11.2 m/s

7 0
3 years ago
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