F=m*a and m is constant on any planet
25000-m*g=m*1.2
10000-m*g=-m*0.80
m*g is the weight
25000/1.2-m*g/1.2=m
10000/0.80-m*g/0.80=-25000/1.2+m*g/1.2 solve for m*g
m*g=(10000/0.80+25000/1.2)/ (1/1.2+1/0.80)
16 kN
Answer:
Answer: <u>Height</u><u> </u><u>is</u><u> </u><u>0</u><u>.</u><u>2</u><u>0</u><u>4</u><u> </u><u>m</u>
Explanation:
At the highest point, it is called the maximum height.
• From third newton's equation of motion:

• At maximum height, v is zero
• u is initial speed
• g is -9.8 m/s²
• s is the height

From the choices provided, the better answer is ' T ' .
Refer to the diagram shown below.
Assume that
(a) The piano rolls down on frictionless wheels,
(b) Wind resistance is negligible.
The distance along the ramp is
d = (1.3 m)/sin(22°) = 3.4703 m
The component of the piano's weight along the ramp is
mg sin(22°)
If the acceleration down the ramp is a, then
ma = mg sin(22°)
a = g sin(22°) = (9.8 m/s²) sin(22°) = 3.671 m/s²
The time, t, to travel down the ramp from rest is given by
(3.4703 m) = 0.5*(3.671 m/s²)*(t s)²
t² = 3.4703/1.8355 = 1.8907
t = 1.375 s
Answer: 1.375 s
by an echo meter
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