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alex41 [277]
3 years ago
8

A syringe initially holds a sample of gas with a volume of 285 ml at 355 k and 1.88 atm. To what temperature must the gas in the

syringe be heated/cooled in order to have a volume of 435 ml at 2.50 atm?
Physics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

The answer to your question is 720.5°K

Explanation:

Data

Volume 1 = 285 ml

Temperature 1 = 355 °K

Pressure 1 = 1.88 atm

Volume 2 = 435 ml

Temperature 2 = ?

Pressure 2 = 2.5 atm

Formula

To solve this problem use the combined gas law

               P1V1 / T1 = P2V2 / T2

- Solve for T2

               T2 = T1P2V2 / P1V1

- Substitution

               T2 = (355)(2.5)(435) / (1.88)(285)

- Simplification

               T2 = 386062.5 / 535.8

- Result

                T2 = 720.53°K

Conclusion

The gas must be heated to 720.5°K

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pochemuha
<h2>Answer: destroy all information about its speed or momentum</h2>

The Heisenberg uncertainty principle postulates that the fact that <u>each particle has a wave associated with it</u>, imposes restrictions on the ability to determine its <u>position</u> and <u>speed</u> at the same time.  

In other words:  

<h2>It is impossible to measure <u>simultaneously </u>(according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle.  </h2>

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3 years ago
An opera singer breaks a crystal glass with her voice. Which best explains why this occurs? The pitch of her voice matches the p
aalyn [17]

The frequency at which the body vibrates breaks is natural frequency. The glass with her voice because the frequency of her voice matches the natural frequency of the glass.

<h3>What is the natural frequency?</h3>

When there is no external force acting on the body unless the body vibrates is known as the natural frequency of vibration.it is denoted by \rm w_n.

when the frequency of a body matches the natural frequency a condition occurs known as resonance.

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brainly.com/question/1123932

3 0
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A wheel moves in the xy plane in such a way that the location of its center is given by the equations xo = 12t3 and yo = R = 2,
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Answer:

the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s  is   P =  104.04 \hat{i} -314.432 \hat{j}

Explanation:

The free-body  diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;

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Now;

V_x = \frac{d}{dt}(12t^3+2) = 36 t^2

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where \omega(angular velocity) = \frac{d\theta}{dt} = \frac{d}{dt}(8t^4)

-V_y = 2*32t^3)\\\\\\-V_y = 2*32(1.7^3)\\\\-V_y = 314.432 \ ft/s

∴ the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s  is   P =  104.04 \hat{i} -314.432 \hat{j}

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