Answer:
$8700
Step-by-step explanation:
Associates cost $800 each, you have 9 associates, so multiply 800 by 9 which gives you: $800x 9= $7200.
Partners cost $1500 each, you have 4 partners, so multiply 1500 by 4 which gives you: $1500x 4=$6000.
Then add the two together like this: $7200+$1500= $8700.
multiply all terms in the second equation by 2 to get the coefficient on the y variable to be -6.

Just use PEMDAS
2+3-4 (5x4)
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction So first is Parenthesis 5x4=20 next will be Addition because there are no exponents 2+3= 5-4= 1 so now we go back to multiplication 20 x 1= 20 so 20 is your answer.
Hope I helped out ^^
Answer: Median= 91; 8th quiz score=86
Step-by-step explanation: The sum of the scores is 8×92=736. Subtract the 6 given scores and then a 100 for the seventh quiz to find the score she got on the 8th quiz, this is an 86. Now that you have all the scores, arrange them all in the least to greatest order and find the average of the middle two numbers (median), which is 91!
Answer:
Step-by-step explanation:
Given that:

Since the given function is equal to zero, then the function :

where;
and



Thus; f(1) < 0 and f(2) > 0