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alexandr402 [8]

2 years ago

10

Tomas drew a rectangle with an area of 6 square centimeters.what is the greatest possible perimeter of this rectangle?Explain pl

ease. i want 20 answers please

1 answer:

LuckyWell [14K]2 years ago

6 0

The answer is 14. Hope it helps!

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write the equation of the line (in slope-intercept form) that passes through the points (2,3 and (5,7)

AfilCa [17]

Answer:

The answer to your question is y = 4/3x + 1/3

Step-by-step explanation:

Data

Point A = (2, 3)

Point B = (5, 7)

Process

1.- Calculate the slope

x1 = 2 y1 = 3

x2 = 5 y2 = 7

m = (y2 - y1)/(x2 - x1)

- Substitution

m = (7 - 3)/(5 - 2)

- Slope

m = 4/3

2.- Find the equation of the line

y - y1 = m(x - x1)

y - 3 = 4/3(x - 2)

y - 3 = 4/3x - 8/3

y = 4/3x - 8/3 + 3

y = 4/3x - 8/3 + 9/3

y = 4/3x + 1/3

8 0

3 years ago

PLEASE HELP!!!!<br><br> IT'S NOT B<br><br> A. 1/4<br> B. 1<br> C. 4<br> D. None of the above

konstantin123 [22]

Answer:

YOUR ANWSER IS C

Step-by-step explanation:

HOPE THIS HELPED

8 0

3 years ago

Which is an irrational number?

N76 [4]

The second one if im not wrong

3 0

3 years ago

Assume that adults have iq scores that are normally distributed with a mean of 100 and a standard deviation of 20. if all iq sco

Svetlanka [38]

Let X be the iq score of adults. X is normally distributed with mean of 100 and standard deviation of 20.

If all iq scores are converted to z -scores then we will get z scores. And the z score is standard normal variable with mean=0 and standard deviation =1

Hence the mean and standard deviation of of all z scores will be 0 and 1 respectively.

6 0

3 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago