Fe2O3 + 2Al ---> Al2O3 + 2Fe
Mole ratio Fe2O3 : Al = 1:2
No. of moles of Fe2O3 = Mass/RMM = 250 / (55.8 * 2 + 16 * 3) = 1.56641604 moles
No. of moles of Al = 150/27 = 5.555555555 moles.
Mole ratio 1 : 2. 1.56641604 * 2 = 3.13283208 moles of Al, but you have 5.555555555 moles of Al. So Al is in excess. All of it won't react.
So take the Fe2O3 and Fe ratio to calculate the mass of iron metal that can be prepared.
RMM of Fe2O3 / Mass of Fe2O3 = RMM of 2Fe / Mass of Fe 159.6 / 250 = 111.6 / x x = 174.8 g of Fe
One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.
Answer:
Because Iodine is a non-polar but water is polar therefore it can not have a hydrogen bond or any permanent dipole-dipole interactions
Answer:
8.324 g
Explanation:
First we <u>convert 750.0 mL into L</u>:
- 750.0 mL / 1000 = 0.750 L
Then we <u>calculate the required number of moles of CaCl₂</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- Molarity * liters = moles
- 0.100 M * 0.750 L = 0.075 mol
Finally we <u>convert 0.075 moles of CaCl₂ into grams</u>, using its <em>molar mass</em>:
- 0.075 mol * 110.98 g/mol = 8.324 g
