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ratelena [41]
3 years ago
8

An electrostatic dust precipitator that is installed in a factory smokestack includes a straight metal wire of length 0.7 m that

is charged approximately uniformly with a total charge 0.8 ×10−7 C. A speck of coal dust (which is mostly carbon) is near the wire, far from both ends of the wire; the distance from the wire to the speck is 1.4 cm. Carbon has an atomic mass of 12 (6 protons and 6 neutrons in the nucleus). A careful measurement of the polarizability of a carbon atom gives the value 1.96 × 10−40 (C · m)/(N/C). (a) Calculate the initial acceleration of the speck of coal dust, neglecting gravity. Your answer must be expressed in terms of , and . You can use other quantities in your calculations, but your final result must not include them. It is convenient to use the "binomial expansion" that you may have learned in calculus, that if . Note that can be negative. (Enter the magnitude. Use the following as necessary: , , , and for the mass of a carbon atom. Use the binomial expansion in your answer.)

Physics
1 answer:
ratelena [41]3 years ago
7 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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Physics help please
zhuklara [117]

Answer: 37.981 m/s

Explanation:

This situation is related to projectile motion or parabolic motion, in which the travel of the ball has two components: <u>x-component</u> and <u>y-component.</u> Being their main equations as follows:

<u>x-component: </u>

x=V_{o}cos\theta t   (1)

Where:

x=52 m is the point where the ball strikes ground horizontally

V_{o} is the ball's initial speed

\theta=0 because we are told the ball is thrown horizontally

t is the time since the ball is thrown until it hits the ground

<u>y-component: </u>

y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}   (2)

Where:

y_{o}=120m  is the initial height of the ball

y=0  is the final height of the ball (when it finally hits the ground)

g=-9.8m/s^{2}  is the acceleration due gravity

Knowing this, let's start by finding t from (2):

<u></u>

0=y_{o}+V_{o}sin(0\°) t+\frac{gt^{2}}{2}   (3)

0=y_{o}+\frac{gt^{2}}{2}  

t=\sqrt{\frac{-2 y_{o}}{g}}   (4)

t=\sqrt{\frac{-2 (120 m)}{-9.8m/s^{2}}}   (5)

t=4.948 s   (6)

Then, we have to substitute (6) in (1):

x=V_{o}cos(0\°) t   (7)

And find V_{o}:

V_{o}=\frac{x}{t}   (8)

V_{o}=\frac{52 m}{4.948 s}   (9)

V_{o}=10.509 m/s   (10)

On the other hand, since we are dealing with constant acceleration (due gravity) we can use the following equation to find the value of the ball's final velocity V:

V=V_{o} + gt (11)

V=10.509 m/s + (-9.8 m/s^{2})(4.948 s) (12)

V=-37.981 m/s (13) This is the ball's final velocity, and the negative sign indicates its direction is downwards.

However, we were asked to find the <u>ball's final speed</u>, which is the module of the ball's final vleocity vector. This module is always positive, hence the speed of the ball just before it strikes the ground is 37.981 m/s (positive).

5 0
3 years ago
 what is the difference between repelling and attracting
enyata [817]

Answer:

Attracting means pulling toward you and repelling means pushing away

Explanation:

3 0
2 years ago
Read 2 more answers
The Surface Pressure at Leh, Ladakh is 800 mb. Now, assuming that Leh is at an altitude of 3500 m and every 100 m increase in he
Basile [38]

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

<h3> Sea level pressure</h3>

Question Parameters:

Ladakh is 800 mb.

<u>assuming </u>that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level <em>pressure</em> we need to add,

Ps=800+350

Ps= 1150 mb

For more information on Pressure visit

brainly.com/question/25688500

8 0
2 years ago
1. If a car travels 400m in 20 seconds how fast is it going?
Marrrta [24]

Answer:

1) 20 m/s

2) 5 m/s

3) 2 m/s

4) 395,000m/9000s

5) 16 km/0.25h

Explanation:

i dunno

5 0
3 years ago
Is this equation balanced? 2HCl + CaCO3 → CaCl2 + H2O + CO2
Serggg [28]

Answer:

Yes it is

Explanation:

the sum moles at the left side equals the sum of moles at the right side

7 0
3 years ago
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