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lutik1710 [3]
3 years ago
12

what is the molecular formula of a compound with an empirical formula of CH and a molar mass of 91.14 G/mole

Chemistry
1 answer:
Tomtit [17]3 years ago
4 0

Answer:hmmmmmmmmmmmmmmmmmmmmmmmmmm

Explanation:

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Severus Snape explains that if you have the molar mass of a compound and the empirical formula of a compound you can determine t
KengaRu [80]

Answer:

The molecular formula of the compound :C_4H_6O_2

Explanation:

The empirical formula of the compound =C_2H_3O

The molecular formula of the compound =C_{2n}H_{3n}O_n

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 86 g/mol

Mass of empirical formula = 43 g/mol

Putting values in above equation, we get:

n=\frac{86g/mol}{43g/mol}=2

The molecular formula of the compound :

C_{2\times 2}H_{3\times 2}O_2=C_4H_6O_2

7 0
3 years ago
2.<br> Why does<br> a chemical equation<br> need to<br> be balanced?
arlik [135]

<em>Answer:</em>

<em>Chemical equations must be balanced to satisfy the law of conservation of matter, that states that matter cannot be produced or destroyed in a closed system. The law of conservation of mass governs the balancing of a chemical equation.</em>

Explanation:

7 0
3 years ago
Which of the following would happen if Earth's moon were half the size that it is now? O The oceans' tidal variations would be s
Brilliant_brown [7]

Answer: A. The oceans‘ tidal would be smaller because the moon would exert less gravitational pull on earths oceans.

Explanation:

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3 0
3 years ago
Why is the following molecule nonpolar and hydrophobic?
algol13

Explanation:

Hydrocarbon shows nonpolar

8 0
3 years ago
The enthalpies of formation of the compounds in the combustion of methane, , are CH4 (g): Hf = –74.6 kJ/mol; CO2 (g): Hf = –393.
algol [13]

Answer:

The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol

Explanation:

The chemical reaction of the combustion of methane is given as follows;

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)

Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor

Where:

CH₄ (g): Hf = -74.6 kJ/mol

CO₂ (g): Hf = -393.5 kJ/mol

H₂O (g): Hf = -241.82 kJ/mol

Therefore, the combustion of 1 mole of methane releases;

-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol

Hence the combustion of 2 moles of methae will rellease;

2 × -802.54 kJ/mol or 1,605.08 kJ/mol.

8 0
3 years ago
Read 2 more answers
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