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lutik1710 [3]
3 years ago
12

what is the molecular formula of a compound with an empirical formula of CH and a molar mass of 91.14 G/mole

Chemistry
1 answer:
Tomtit [17]3 years ago
4 0

Answer:hmmmmmmmmmmmmmmmmmmmmmmmmmm

Explanation:

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The reaction is in the gas phase, so the equilibrium constant is expressed in terms of the partial pressures (P) of the products and reactants, as follows:

Kp = \frac{P^{2}_{SO_{3}  } }{P_{SO_{2}} ^{2}P_{O_{2}}  }

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P(SO₃) = 2.6 atm

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We need Kp for this reaction. We can assume that in Appendix 4 we found that Kp = 7 x 10²⁴.

Then, we introduce the data in the equilibrium constant expression to calculate the partial pressure f SO₂ (PSO₂), as follows:

P_{SO_{2} } = \sqrt{\frac{P_{SO_{3} } ^{2} }{Kp P_{O_{2} } } } = \sqrt{\frac{(2.6 atm)^{2} }{(7 x 10^{24)}(0.43 atm) } } = 1.5 x 10^{-12} atm

Therefore, the partial pressure of SO₂ is 1.5 x 10⁻¹² atm (for the given Kp).

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