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2 years ago

How many moles are in 8.0 gram sample of C3H4

Chemistry

1 answer:

Alika [10]2 years ago

7 0

Answer:

0.18 mol C₃H₈

Explanation:

to find the mole you have to convert the 8.0grams into moles.

8.0g C₃H₈ 1 mol C₃H₈

1 44.0g C₃H₈

*Pretend that those are a table*

I got 44.0g because Carbon is 12.0g you multiply that 3 times because it has a subscript of 3 and do the same for Hydrogen (1.0 x 8) then add those which would be 44.0g.

1 mol of C₃H₈ = 44.0g C₃H₈

now just mulitply and divide them.

8.0g x 1 = 8.0

1 x 44.0g = 44.0

8.0/44.0 = 0.18 mol C₃H₈

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3 years ago

12. A voltaic cell consists of a chromium electrode dipped in a 1.20 M chromium (III) nitrate

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2 years ago

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Zinaida [17]

Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

Mass of iron bar

= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

$= 8.16 \times 10^{ - 6} \: kg$

$\boxed{density = \frac{mass}{volume} }$

Density of iron bar

$= \frac{0.0642}{8.16 \times 10^{ - 6} }$

= 7870 kg/m³ (3 s.f.)

$\boxed{mass = density \: \times volume}$

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

$= 12 \times 10^{ - 6} \: m^{3} \\ = 1.2 \times 10^{ - 5} \: m ^{3}$

Mass of brick

= 151 g

= 151 ÷ 1000 kg

= 0.151 kg

Density of brick

= mass ÷ volume

$= \frac{0.151} {1.25 \times 10^{ - 5} } \\ = 12600 \: kg/ {m}^{3}$

(3 s.f.)

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3 years ago