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3 years ago

if a 500.0-g block of metal absorbs 5,016J of heat when its temperature changes from 20.00 Celcius, what is the specific heat?

1 answer:

4 0

Correction: The temperature change is from 20 °C to 30 °C.

Answer:
Cp = 1.0032 J.g⁻¹.°C⁻¹

Solution:

The equation used for this problem is as follow,

Q = m Cp ΔT ----- (1)

Where;
Q = Heat = 5016 J

m = mass = 500 g

Cp = Specific Heat Capacity = ??

ΔT = Change in Temperature = 30 °C - 20 °C = 10 °C

Solving eq. 1 for Cp,

Cp = Q / m ΔT

Putting values,
Cp = 5016 J / (500 g × 10 °C)

Cp = 1.0032 J.g⁻¹.°C⁻¹

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Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

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As solid is changing to gas, randomness increases and thus sign of $\Delta S$ is positive.

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As gas is changing to solid, randomness decreases and thus sign of $\Delta S$ is negative.

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As 7 moles of reactants are converted to 8 moles of products , randomness increases and thus sign of $\Delta S$ is positive.

f) $I_2(s)\rightarrow I_2(g)$

As solid is changing to gas, randomness increases and thus sign of $\Delta S$ is positive.

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