Torque acting dowward = 6 x 0.5 = 3 Nm
Torque acting to the right = 5 x 1 = 5 Nm
5 - 3 = 2 Nm
inertia = 1/2 mr^2
0.5 x 10 x 1^2 = 5 kg-m^2
2/5 = alpha = 0.4 rad /s^2
Hope this helps
Answer:
The induced emf in the coil is 0.522 volts.
Explanation:
Given that,
Radius of the circular loop, r = 9.65 cm
It is placed with its plane perpendicular to a uniform 1.14 T magnetic field.
The radius of the loop starts to shrink at an instantaneous rate of 75.6 cm/s , 
Due to the shrinking of radius of the loop, an emf induced in it. It is given by :

So, the induced emf in the coil is 0.522 volts.
Answer:
1497×10⁵ km
Explanation:
Speed of light in vacuum = 3×10⁵ km/s
Time taken by the light of the Sun to reach the Earth = 8 min and 19 s
Converting to seconds we get
8×60+19 = 499 seconds
Distance = Speed × Time

1 AU = 1497×10⁵ km
The Sun is 1497×10⁵ km from Earth
Answer:
(a): emf =
(b): Amplitude of alternating voltage = 20.942 Volts.
Explanation:
<u>Given:</u>
- Area of the coil = A.
- Number of turns of coil = N.
- Magnetic field = B
- Rotation frequency = f.
(a):
The magnetic flux through the coil is given by

where,
= area vector of the coil directed along the normal to the plane of the coil.
= angle between
and
.
Assuming, the direction of magnetic field is along the normal to the plane of the coil initially.
At any time t, the angle which magnetic field makes with the normal to the plane of the coil is 
Therefore, the magnetic flux linked with the coil at any time t is given by

According to Faraday's law of electromagnetic induction, the emf induced in the coil is given by

(b):
The amplitude of the alternating voltage is the maximum value of the emf and emf is maximum when 
Therefore, the amplitude of the alternating voltage is given by

We have,

Putting all these values,
