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fomenos
3 years ago
9

will mark brainliest. The speed of sound is 340 m/s where a tuning fork produces the second resonance position above a closed ai

r column that is 49.8 cm in length. The frequency of the tuning fork is ___ Hz.
Physics
2 answers:
vodomira [7]3 years ago
8 0

Answer:

Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)

Explanation:

Given:

Speed of sound = 340 m/s

Length of resonance position above a closed air column = 49.8 cm = 0.498 m

Find:

Frequency of the tuning fork

Computation:

Frequency of the tuning fork[second resonance] = 3v / 4l

Frequency of the tuning fork[second resonance] = 3(340) / 4(0.498)

Frequency of the tuning fork[second resonance] = 512.04

Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)

lakkis [162]3 years ago
3 0

Answer:

The frequency is 512 Hz.

Explanation:

speed, v = 340 m/s

length, L = 49.8 cm = 0.498 m

let the frequency is f.

f =\frac{3 v}{4 L}\\\\f = \frac{3 \times 340 }{4\times 0.498}\\\\f = 512 Hz

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3 years ago
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c. selenium

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2 years ago
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You are an evolutionary biologist studying a population of bats in the rain forest in Brazil. Most of the population possesses m
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2 years ago
An object is pulled to the left by a force of 50 N. The same amount of force pulls it to the right. The object will ____.
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<h2><u>Required</u><u> </u><u>Answer</u><u>:</u></h2>

The body will <u>stay at rest </u>(Option D). It is because a force of magnitude 50 N is pulled towards left and another force is pulling it towards right with same magnitude 50 N. So, the direction of force is opposite and magnitude is same i.e. 50 N. So, they will cancel each other and net force is 0. Hence, there would be no acceleration.

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