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3 years ago

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There is a(n) __________ relationship between an object's weight and its mass.

1 answer:

Mkey [24]3 years ago

4 0

There is a direct relationship between between an object's weight and its mass.

Weight is actually the force of gravity on the object's mass and it can be calculated by multiplying the object's mass and the acceleration due to gravity. The higher the mass, the higher the weight and the lower the mass, the lower the object's weight. Thus, the relationship is direct.

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A car goes from 0 to 60 mi/h north in 5 seconds. what is the car's acceleration?

Tomtit [17]

Answer:

<h2>17.6 feet / second ^2</h2>

Explanation:

Explanation: 0 to 60 miles per hour means 0 to 88 feet/sec in five seconds (60 multiplied by 5280 (feet in one mile) divided by 3600 (seconds in an hour). The acceleration is 17.6 feet / second ^2.

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2 years ago

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At its lowest setting a centrifuge rotates with an angular speed of calculate the angular velocity

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3 years ago

A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a

ss7ja [257]

Answer:

P = 1471500 [Pa]

Explanation:

We must remember that pressure is defined as the relationship between Force over the area.

$P=F/A$

where:

P = pressure [Pa] (units of pascals)

F = force [N] (units of Newtons)

A = area of contact = 4 [cm²]

But first we must convert from cm² to m²

$A = 4[cm^{2}]*\frac{1^{2} m^{2} }{100^{2} cm^{2} }$

A = 0.0004 [m²]

Also, the weight should be calculated as follows:

$w = m*g$

where:

m = mass = 60 [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

$w = 60*9.81\\w = 588.6[N]$

And the pressure:

$P=588.6/0.0004\\P=1471500 [Pa]$

Because 1 [Pa] = 1 [N/m²]

8 0

3 years ago

A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet

Serga [27]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The work done by the spring is = $0.27 J$

Explanation:

Force = torque × length

Given

F = 9.13 N

length (L) = 5.91 cm = 0.0591 m [Note 1 m = 100 cm ]

considering the formula above

$9.13 = k * 0.0591$ where k denotes torque

$k = 154.48\ N/m$

Energy Stored $= \frac{1}{2} k x^2$

$= \frac{1}{2} * 154.48 * (0.0591)^2$

$= 0.27J$

8 0

3 years ago

g A ball thrown straight up into the air is found to be moving at 7.94 m/s after falling 2.72 m below its release point. Find th

kati45 [8]

The ball has height <em>y</em> and velocity <em>v</em> at time <em>t</em> according to

<em>y</em> = <em>v</em>₀ <em>t</em> - 1/2 <em>g</em> <em>t</em> ²

and

<em>v</em> = <em>v</em>₀ - <em>g t</em>

where <em>v</em>₀ is its initial speed and <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.

The ball is falling with a velocity of 7.94 m/s when it's 2.72 m below the release point, which at time <em>t </em>such that

-2.72 m = <em>v</em>₀ <em>t</em> - 1/2 <em>g</em> <em>t</em> ²

-7.94 m/s = <em>v</em>₀ - <em>g t</em>

Solve for <em>t</em> in the second equation:

<em>t </em>= (<em>v</em>₀ + 7.94 m/s)/<em>g</em>

Substitute this into the first equation and solve for <em>v</em>₀ :

-2.72 m = <em>v</em>₀ (<em>v</em>₀ + 7.94 m/s) /<em>g</em> - 1/2 <em>g</em> ((<em>v</em>₀ + 7.94 m/s)/<em>g</em>)²

-2.72 m = <em>v</em>₀²/<em>g</em> + (7.94 m/s) <em>v</em>₀/<em>g</em> - 1/2 (<em>v</em>₀ + 7.94 m/s)²/<em>g</em>

2 (-2.72 m) <em>g</em> = 2<em>v</em>₀² + 2 (7.94 m/s) <em>v</em>₀ - (<em>v</em>₀ + 7.94 m/s)²

2 (-2.72 m) (9.80 m/s²) = 2<em>v</em>₀² + (15.9 m/s) <em>v</em>₀ - (<em>v</em>₀² + (15.9 m/s) <em>v</em>₀ + 63.0 m²/s²)

-53.3 m²/s² = <em>v</em>₀² - 63.0 m²/s²

<em>v</em>₀² = 9.73 m²/s²

<em>v</em>₀ = 3.12 m/s

3 0

3 years ago