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3 years ago

There is a(n) __________ relationship between an object's weight and its mass.

1 answer:

4 0

There is a direct relationship between between an object's weight and its mass.

Weight is actually the force of gravity on the object's mass and it can be calculated by multiplying the object's mass and the acceleration due to gravity. The higher the mass, the higher the weight and the lower the mass, the lower the object's weight. Thus, the relationship is direct.

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A student performs an activity using a sheet of paper, a magnet, and a steel ball. The image shows the setup. The student observ

son4ous [18]

Answer:b

Explanation:

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3 years ago

Read 2 more answers

A wall has inner and outer surface temperatures of 25◦C and 8◦C, respectively. The interior and exterior air temperatures are 35

Angelina_Jolie [31]

Answer:

a) $\frac{\dot Q}{A} =60\ W.m^{-2}$

b) $\frac{\dot Q}{A} =110\ W.m^{-2}$

c) The wall may not be under steady because the two surfaces of the wall are exposed to the air at different temperatures and they have different convective coefficient.

Explanation:

Given:

temperature of the inner surface of the wall, $T_i=25^{\circ}C$

temperature of the outer surface of the wall, $T_o=8^{\circ}C$

temperature of the air outside, $T_{ao}=-3^{\circ}C$

temperature of the air inside, $T_{ai}=35^{\circ}C$

coefficient of heat convection on outside, $h_o=10\ W.m^{-2}.K^{-1}$

coefficient of heat convection on inside, $h_i=6\ W.m^{-2}.K^{-1}$

The heat flux between the interior air and the wall:

The convective heat transfer rate is given as,

$Q=h_i.A.\Delta T$

$\Rightarrow \frac{\dot Q}{A} =h_i\times (T_{ai}-T_i)$

$\frac{\dot Q}{A} =6\times (35-25)$

$\frac{\dot Q}{A} =60\ W.m^{-2}$

The heat flux between the exterior air and the wall:

$\Rightarrow \frac{\dot Q}{A} =h_o\times (T_{ao}-T_i)$

$\frac{\dot Q}{A}=10\times (8-(-3))$

$\frac{\dot Q}{A} =110\ W.m^{-2}$

The wall may not be under steady because the two surfaces of the wall are exposed to the air at different temperatures and they have different convective coefficient.

4 0

4 years ago

A 51.0 g stone is attached to the bottom of a vertical spring and set vibrating. If the maximum speed of the stone is 16.0 cm/s

Nina [5.8K]

Answer:

A) 32.22 N/m b) 0.0156 m c) 4 Hz

Explanation:

Using Hooke's law;

T = 2π √m/k where m is mass of the body in kg and k is the force constant of the spring N/m and T is the period of vibration in s.

M = 51 g = 51 / 1000 in kg = 0.051kg

Make k subject of the formula

T/2π = √m / k

Square both sides

T^2 / 4π^2 = m/k

Cross multiply

K = 4 π^2 * m/T^2

K = 4 * 3.142 * 3.142 * 0.051/ 0.25^2= 32.22N/m

B) using Hooke's law;

F = k e where e is the maximum displacement of the spring from equilibrium point called amplitude

F= weight of the body = mass * acceleration due to gravity = 0.051*9.81

0.5 = 32.22 * e

e = 0.5/32.22 = 0.0156 m

C) frequency is the number of cycle completed in a second = 1 / period

F = 1 / 0.25 = 4Hz

6 0

3 years ago

If a car is traveling on the highway at a constant velocity, the force that pushes the car forward must be A. equal to the weigh

Gala2k [10]

the correct answer is c

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4 years ago

Professional baseball pitchers deliver pitches that can reach the blazing speed of 100 mph (miles per hour). A local team has dr

Wittaler [7]

Answer:

A. ) K =126. 7 J

B. ) h= 91.1 m.

Explanation:

Assuming no air resistance, once released by the pitcher, the speed must keep constant through all the trajectory, so the kinetic energy of the ball can be expressed as follows:

$K = \frac{1}{2}*m*v^{2} = \frac{1}{2}*0.142 kg*(42.24m/s)^{2} = 126.7 J (1)$

Neglecting air resistance, total mechanical energy must be the same at any point, so, if we choose the ground level as the zero reference level for the gravitational potential energy, and assuming that the ball attains this kinetic energy just before striking ground, this value must be equal to the gravitational potential energy just before be dropped, so we can write the following equality:

$U_{o} = K_{f} = 126. 7 J (2)$

⇒ m*g*h = 126. 7 J

Solving for h, we get:

$h = \frac{K_{f}}{m*g} = \frac{126.7J}{0.1420kg*9.8m/s2} = 91.1 m (3)$

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3 years ago