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Delicious77 [7]
3 years ago
13

Technician A says twisted/shielded wire carries low current, and repairs to the wire must not increase the resistance of the cir

cuit. Technician B says twisted/shielded wire carries high current, and any repairs must not increase the resistance of the circuit. Who is correct?
Physics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

None of the them has a complete answer .

Explanation:

The current in a wire is a function of the conduction element geometry inside the cable, given by the resistance and the conduction area. So saying twisted/shield, is not giving us any information about the current rating of the wire.

Repairs to the wire may affect the area of the conductor, reducing the effective surface of conduction. But a well-executed repairing must made an insignificant change in the resistance. So it's not a definitive concept.

A twisted/shield wire is generally used for signal transport, as it's configured to reduce the noise in the data transmission.  

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By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows, with m1 = 12.1 kg and
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Answer:

14.8 kg

Explanation:

We are given that

m_1=43.7 kg

m_2=12.1 kg

g=9.8 m/s^2

a=\frac{1}{2}(9.8)=4.9 m/s^2

We have to find the mass of the pulley.

According to question

T_2-m_2 g=m_2 a

T_2=m_2a+m_2g=m_2(a+g)=12.1(9.8+4.9)=177.87 N

T_1=m_1(g-a)=43.7(9.8-4.9)=214.13 N

Moment of inertia of pulley=I=\frac{1}{2}Mr^2

(T_2-T_1)r=I(-\alpha)=\frac{1}{2}Mr^2(\frac{-a}{r})=\frac{1}{2}Mr(-4.9)

Where \alpha=\frac{a}{r}

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