Answer:
mass of the planet and its distance from other objects
Explanation:
mass of the planet and its distance from other objects determine the strength of its gravitational force on other objects
I think the answer is b Behaviors of the electrons help cause both the shininess and the conductivity of metals
3.32µF and 1.64µF
Since, you haven't actually asked a question, I am going to make a guess on what the question is based upon the data provided. My educated guess is "What are the values of the two capacitors?"
The formula for the Capacitive reactance is
X = 1/(2*pi*f*C)
where
X = reactance
f = frequency
C = capactance
Let's solve for C
X = 1/(2*pi*f*C)
CX = 1/(2*pi*f)
C = 1/(2*pi*f*X)
Now with the capacitors in parallel, we have a reactance of:
I = V/X
IX = V
X = V/I
X = 12.3/0.56
X = 21.96428571
So the capacitance is:
C = 1/(2*pi*f*X)
C = 1/(2*pi*1460*21.96428571)
C = 4.96307x10^-6 = 4.96307 µF
And with the capacitors in series we have a reactance of:
X = V/I
X = 12.3/0.124
X = 99.19354839
So the capacitance is:
C = 1/(2*pi*f*X)
C = 1/(2*pi*1460*99.19354839)
C = 1.09896x10^-6 = 1.09896 µF
Now we can setup two equations with 2 unknowns.
4.96307 = x + y
1.09896 = 1/(1/x + 1/y)
y = 4.96307 - x
1.09896 = 1/(1/x + 1/(4.96307 - x))
1.09896 = 1/((4.96307 - x)/(x(4.96307 - x)) + x/(x(4.96307 - x)))
1.09896 = 1/(((4.96307 - x)+x)/(x(4.96307 - x)))
1.09896 = 1/(4.96307/(x(4.96307 - x)))
1.09896 = x(4.96307 - x)/4.96307
5.45422 = x(4.96307 - x)
5.45422 = 4.96307x - x^2
0 = 4.96307x - x^2 - 5.45422
0 = -x^2 + 4.96307x - 5.45422
We now have a quadratic equation. Use the quadratic formula to solve, getting roots of 3.320460477 and 1.642609523. You may notice that those 2 values add up to 4.96307. This is not coincidence. Those are the values of the two capacitors in µF. Rounding to 3 significant figures gives us 3.32µF and 1.64µF.
The loudness of the sound at the rock concert, where the intensity of the sound is1 x 10⁻¹ Wm⁻² is 110 dB.
Here we are dealing with loudness which is the perception of the Intensity of the sound.
The formula to refer to in order to find the value of the loudness of a sound is ,
db= 10log(I/I₀)
As we are provided with the current intensity which is 1 x 10⁻¹ Wm⁻². and the initial intensity which is 1 x 10⁻¹² Wm⁻².
So, by substituting the required values in the formula we get
db= 10 * log( 1 x 10⁻¹ /1 x 10⁻¹²)
= 10 * 11 log(10)
= 110
So, the result is 110 dB.
To know more about the intensity of sound refer to the link brainly.com/question/9323731?referrer=searchResults.
To know more about questions related to loudness refer to the link brainly.com/question/21094511?referrer=searchResults.
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