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3 years ago

NEED HELP ASAP!!! really confused. can someone explain how to do it? (Stoichiometry)

Chemistry

1 answer:

Katena32 [7]3 years ago

8 0

Answer:

The answer to your question is below

Explanation:

Data

mass of Gold = 35.12 g

mass number of gold = 197 g (from the periodic table)

1.- To calculate the number of moles use proportions

197 g of gold ----------- 1 mol

35.12 g of gold -------- x

x = (35.12 x 1)/197

x = 0.18 moles of gold

2.- To calculate the number of atoms also use proportions and the Avogadro's number.

1 mol of gold ------------ 6.023 x 10 ²³ atoms

0.18 moles of gold ----- x

x = (0.18 x 6.023 x 10²³) / 1

x = 1.084 x 10²³ atoms

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lara31 [8.8K]

Answer:

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Explanation:

4 0

2 years ago

Plutonium-236 is an alpha emitter with a half-life of 2.86 years. how long will it take for the 1.10 mg sample of pu−236 to deca

lawyer [7]

1.1 / 2 = .7 --> 2.86 yrs

.7 / 2 = .45 —> 5.72 yrs

.45 / 2 = .225 —> 8.58 yrs

.225 / 2 = .1125 —> 11.44 yrs

So, for the sample of plutonium to reach .140 mg it should take a little less than 11.44 years.

Hope this helps

5 0

3 years ago

Acids are defined as proton donors since they release hydrogen ions. a. True b. False

Vladimir [108]

This is true they are defined as protons

4 0

3 years ago

The atomic mass of Gallium is 69.72 AMU. The masses of the naturally occurring isotopes are 68.9257 AMU and 70.908 AMU for Ga-69

Mashcka [7]

Answer:

40.7% abundance of Ga-71

59.93% abundance of Ga-69

Explanation:

Given data:

Average atomic mass of Ga = 69.72 amu

Atomic mass of Ga-69 = 68.9257 amu

Atomic mass of Ga-71 = 70.908 amu

Percent abundance of each isotope = ?

Solution;

we know there are two naturally occurring isotopes of Ga.

First of all we will set the fraction for both isotopes

X for the isotopes having mass 68.9257

1-x for isotopes having mass 70.908

we will use the following equation,

68.9257x + 70.908 (1-x) = 69.72

68.9257x +70.908 - 70.908x = 69.72

68.9257x - 70.908x = 69.72 - 70.908

-1.9823x = - 1.188

x= 1.188/1.9823

x= 0.5993

0.5993 × 100 = 59.93 %

59.93 % is abundance of Ga-69 because we solve the fraction x.

now we will calculate the abundance of Ga-71.

(1-x)

1 - 0.5993 = 0.4007

0.4007× 100= 40.7 %

40.7 % for Ga-71.

3 0

3 years ago

An electrode has a potential of 1.201 V with respect to a saturated silver-silver chloride electrode. What would the electrodes

fredd [130]

Answer:

The potential wrt. calomel is 1.254 V

Explanation:

Given:

Potential wrt. silver chloride $E_{Ag} = 1.201$ V

Potential wrt. saturated silver chloride $E = 0.197$ V

Potential wrt. SCE $E_{Hg} = 0.241$ V

Now potential wrt. hydrogen is given by,

$= 1.201- 0.197$

$= 1.004$ V

And we find for potential wrt. calomel,

$=$ potential wrt. hydrogen + potential wrt. SEC

$= 1.004 +0.241$

$= 1.254$ V

Therefore, the potential wrt. calomel is 1.254 V

7 0

3 years ago