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hram777 [196]
3 years ago
11

Please help me ASAP I’ll mark Brainly

Chemistry
1 answer:
poizon [28]3 years ago
3 0

Answer:

Electrical, heat, and light

Explanation:

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A 4.00 g sample of a metal (specific heat = 0.600 J g-1°C-1 is heated to 75 degrees Celcius and then dropped into 165 g of water
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Answer:

28.16 °C

Explanation:

Considering that:-

Heat gain by water = Heat lost by metal

Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)

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Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)

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For metal:

Mass = 4.00 g

Initial temperature = 75 °C

Specific heat of water = 0.600 J/g°C

So,  

165\times 4.184\times (T_f-28)=4.00\times 0.600\times (75-T_f)

690360\left(T_f-28\right)=2400\left(75-T_f\right)

692760T_f=19510080

T_f = 28.16\ ^0C

<u>Hence, the final temperature is 28.16 °C</u>

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