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Whitepunk [10]
3 years ago
9

The following reaction was performed in a sealed vessel at 760 ∘C : H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at

concentrations of [H2]=3.85M and [I2]=2.35M . The equilibrium concentration of I2 is 0.0500 M . What is the equilibrium constant, Kc, for the reaction at this temperature?
Chemistry
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

The equilibrium constant is 273.0322

Explanation:

For the given chemical reaction ,

ICE table can be written as -

                             H₂(g)    +      I₂(g)    ⇄     2HI(g)

initial moles         3.85             2.35                -

at equilibrium      3.85 - x       2.35 - x           2x

From question , at equilibrium the concentration of I₂ = 0.0500 M

The concentration of I₂ ( ICE table ) = concentration of I₂ (given in question )

2.35 - x = 0.0500

x = 2.3

Putting the value of x in ICE table , to obtain the concentration  terms as-

[H₂] = 3.85 - x

[H₂] = 3.85 - 2.3

[H₂] = 1.55 M

[HI] = 2x

[HI] = 2* 2.3

[HI] = 4.6 M

[I₂] = 0.0500M       (Given)

Equilibrium Constant ( Kc )

The value of equilibrium constant is written as the concentration of the products each raised to the power of their respective stoichiometry by the concentration of reactants each raised to the power of their respective stoichiometry.

Kc = [HI]² / [H₂][I₂]

Kc = ( 4.6 )² / (1.55)*(0.0500)

Kc = 273.0322 .

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Answer:

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Explanation:

In the process:

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3 years ago
The mass and volume of each box is given in the chart below. Calculate the density of each box. Density = Mass/ volume which box
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Box C will have the greatest density.

All boxes have the same volume.

Explanation:

We calculate the density using the following formula:

density = mass / volume

density of Box A = 10 g / 20 cm³ = 0.5 g/cm³

density of Box B = 30 g / 20 cm³ = 1.5 g/cm³

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Two scientists wrote a paper detailing their research and conclusions and submitted it to a scientific journal. Several months l
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Answer:

The element is strontium and the number of neutrons it have is 51.

Explanation:

Based on the given information, the ionic compound is,  

XCl₂ ⇔ X₂⁺ + 2Cl⁻

X2+ is the ion of the mentioned element

As mentioned in the given question, the number of electrons of the element X is 36 and as seen from the reaction the charge present on the ion is +2. Now the atomic number will be,  

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Based on the periodic table, the atomic number 38 is for strontium element, and the sign of strontium is Sr. Hence, the element X is Sr.  

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