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frez [133]
3 years ago
9

A plastic bottle partially filled with water floats on water, even though the density of the plastic (1.2 g/cc) is more than tha

t of water. Why is that?
Physics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

True the plastic will float because of the principle of flotation or buoyancy

Explanation:

Buoyancy explains it all!!

Buoyancy  is the upward force/upthrust experienced by a body immersed totally or partially in a liquid.

According to the principle of flotation:

<em>"when a body is totally or partially immersed in liquid it experiences an upthrust which is equal to the volume of fluid displaced"</em>

The plastic will float due to the fact the average density of the total volume of the plastic and the air inside it is less than the same volume of water it is floating in

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How are elements and compounds similar
sergejj [24]
Compound and events are pure substance
4 0
3 years ago
In separate experiments, a large number of particles (all with the same charge, but with a wide variety of masses and speeds) ar
likoan [24]

Answer:

  they have the same mass

Explanation:

The force applied by the field is a function of the charge and velocity, so the acceleration experienced by a particle will be dependent upon its mass. Particles in orbits with the same radius are exhibiting the same acceleration, so must have the same mass.

7 0
3 years ago
An object is thrown straight up with an initial velocity of 10 m/s, and there is an air resistance force causing an acceleration
lana [24]

Answer:

Vf= 7.29 m/s

Explanation:

Two force act on the object:

1) Gravity

2) Air resistance

Upward motion:

Initial velocity = Vi= 10 m/s

Final velocity = Vf= 0 m/s

Gravity acting downward =  g = -9.8 m/s²

Air resistance acting downward = a₁ = - 3 m/s²

Net acceleration = a = -(g + a₁ ) = - ( 9.8 + 3 ) = - 12.8 m/s²

( Acceleration is consider negative if it is in opposite direction of velocity )

Now

2as = Vf² - Vi²

⇒ 2 * (-12.8) *s = 0 - 10²

⇒-25.6 *s = -100

⇒ s = 100/ 25.6

⇒ s = 3.9 m

Downward motion:

Vi= 0 m/s

s = 3.9 m

Gravity acting downward =  g = 9.8 m/s²

Air resistance acting upward = a₁ = - 3 m/s²

Net acceleration = a = g - a₁  =  9.8 - 3  = 6.8 m/s²

Now

2as = Vf² - Vi²

⇒ 2 * 6.8 * 3.9 = Vf² - 0

⇒ Vf² = 53. 125

⇒ Vf= 7.29 m/s

8 0
3 years ago
German physicist Werner Heisenberg related the uncertainty of an object's position (Δx) to the uncertainty in its velocity (Δ???
fredd [130]

Answer:

\Delta x = 5.47 \times 10^{-9} m

Explanation:

As we know by the principle of uncertainty that the product of uncertainty in position and uncertainty in momentum is given as

\Delta x \times \Delta P = \frac{h}{4\pi}

so here we know that

\Delta v = 0.01 \times 10^6 m/s

m = 9.11 \times 10^{-31} kg

so we have

\Delta x \times (9.11 \times 10^{-31})(0.01 \times 10^6) = \frac{6.26 \times 10^{-34}}{4\pi}

\Delta x = 5.47 \times 10^{-9} m

5 0
3 years ago
If the crate shown here is moving at a constant speed in a straight line and the force applied is 310 N, what is the magnitude o
larisa86 [58]

Answer:

f_k = 310N

the answer is A.

Explanation:

Using the laws of newton:

∑F = ma

where ∑F is the sumatory of forces acting in the system, m the mass and a the acelertion of the system.

Then, if the block is moving with constant velocity, its aceleration is equal to 0, so:

∑F = m(0)

∑F = 0

It means that:

F -f_k = 0

where F is the force applied and f_k is the friction force. Replacing the value of F, we get:

310N -f_k = 0

Finally, solving for f_k:

f_k = 310N

8 0
3 years ago
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