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3 years ago

Explain why the bright spectral lines of light emitted from the atoms of an element are unique to that element

1 answer:

eduard3 years ago

4 0

<span>If you want the Lewis diagram of arsenic, it is a single element, and not much of a "structure". Simply place five dots on the four sides of an imaginary square around the symbol As. Two of the dots are paired, three are unpaired.

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How do amplitude and frequency affect light energy? help asap !!!!!!

Lubov Fominskaja [6]

So, I’m assuming that we’re treating light as a propagating wave.

Amplitude measures the amount of energy transported by a wave, thus amplitude squared is directly proportional to the light’s energy. The higher the amplitude, the higher the energy.

Energy is also directly proportional to the frequency of a wave, the higher the frequency, the higher the energy.

I took my second answer from the formula below:

E=cf

7 0

3 years ago

A friend rides, in turn, the rims of three fast merry-go-rounds while holding a sound source that emits isotropically at a certa

Aliun [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The Ranking of the curve according to their speed would be equal Rank because $v_1 =v_2 =v_3$

The first frequency would have a higher rank compared to the other two which will have the same ranking when ranked with respect to their angular velocities because

$w_1 >w_2 = w_3$

The ranking of the second third frequency would be the same but their ranking would be greater than that of the first frequency because

$r_2 =r_3 >r_1$

Explanation:

Mathematically Frequency can be represented as

$F = \frac{v}{\lambda}$

Where $\lambda$ is the wavelength and v is the velocity

Now looking at the diagram we see that

For the first frequency we have

Let the wavelength be $\lambda_1 = \lambda$ , and the frequency $F_1 = F$

For the second frequency

Let the wavelength be $\lambda_2 = 2 \lambda$ , and the frequency $F_2 = \frac{F}{2}$

For the third frequency

Let the wavelength be $\lambda_3 = 2\lambda$ , and the frequency $F_3 = \frac{F}{2}$

To obtain v for each of the frequency we make v the subject in the equation above for each frequency

So,

For the first frequency we have

$v_1 = \lambda_1 F_1 = \lambda F$

For the second frequency

$v_2 = \lambda_2 F_2 = 2 \lambda*\frac{F} {2} = \lambda F$

For the third frequency

$v_3 = \lambda_3 F_3 = 2 \lambda*\frac{F} {2} = \lambda F$

Hence

The Ranking of the curve according to their speed would be equal Rank because $v_1 =v_2 =v_3$

Mathematically angular speed can be represented as

$w = 2 \pi f$

For the first frequency we have

$w_1 = 2\pi F_1 = 2 \pi F$

For the second frequency

$w_2 = 2 \pi F_2 = 2 \pi \frac{F}{2} = \pi F$

For the third frequency

$w_3 = 2 \pi F_3 = 2 \pi \frac{F}{2} = \pi F$

Hence

The first frequency would have a higher rank compared to the other two which will have the same ranking when ranked with respect to their angular velocities because

$w_1 >w_2 = w_3$

Mathematically the relationship between the angular velocity and the linear velocity can be represented as

$v = wr$

=> $r = \frac{v}{w}$

Since the linear velocity is constant we have that

$r \ \alpha \ \frac{1}{w}$

This means that r varies inversely to the angular velocity ,What this means for ranking due to the radius is that the ranking of the second third frequency would be the same but their ranking would be greater than that of the first frequency because

$r_2 =r_3 >r_1$

5 0

3 years ago

How do narwhals breathe

NNADVOKAT [17]

Answer:

Like all mammals (including whales and dolphins) narwhals need oxygen. ... Fish use their gills to extract oxygen from the water. But narwhals, like us, use their lungs to breathe.

Explanation:

5 0

3 years ago

How is sound produced? Name its three<br>characteristics.

nydimaria [60]

Answer:

1.loudness

2.pitch

3.shrillness

5 0

4 years ago

The further the planets is from the sun the is its year

Genrish500 [490]

The further the planet is from the sun the smaller the year is

7 0

4 years ago