The distance traveled by first car is 50t + 100.
The distance traveled by second car is 70t.
The distance between the two cars after time, t is d = 100 - 20t.
The ratio of the distance traveled by the cars is (70t) / (50t + 100).
<h3>
Distance traveled by each vehicle is calculated as follows;</h3>
The distance traveled by each vehicle at the given time is calculated as follows;
<h3>Distance traveled by first car</h3>
D₁ = speed x time
D₁ = 50(t + 2)
D₁ = 50t + 100
<h3>Distance traveled by the second car</h3>
D₂ = 70t
<h3>Distance between the two cars after time, t</h3>
d = D₁ - D₂
d = (50t + 100) - 70t
d = 100 - 20t
<h3>Ratio of the distance traveled by the cars</h3>
D₂/D₁ = (70t) / (50t + 100)
Learn more about distance traveled by a vehicle here: brainly.com/question/6504879
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Answer:
3
Step-by-step explanation:
subtract 3y from both sides
add 9 to both sides
3y=12x+9
divide everything by 3
y=4x+3
y-intercept is 3
Answer:
the answer is 2x-22
Step-by-step explanation:
Answer:
use photomath and if that dont work use m a t h w a y
Step-by-step explanation:
Step-by-step explanation:
Therefore,
(x+20) + (x-10) + (2x-30) = 180° (Sum of interior angles of a triangle)
Or, x+x+2x+20-10-30 = 180°
Or, 4x-20 = 180°
Or, 4x= 180+20
Or, 4x= 200°
Or, x= 200°/4
Therefore, x= 50°
So,
(x+20)
= 50+20
=70°
(x-10)
= 50-10
40°
(2x-30)
= 2×50-30
=100-30
=70°
Hope it helped, If it did, please mark it as the brainliest answer :)
