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Oduvanchick [21]
3 years ago
5

For which one of the following is ΔHfo zero?

Chemistry
2 answers:
Vlada [557]3 years ago
6 0
The answer is most likely C
Sholpan [36]3 years ago
3 0
The standard enthalpy of formation is zero for B and D since by definition, the standard enthalpy of formation for an element at its standard state is zero. The monatomic oxygen is not the standard state of oxygen while carbon dioxide is already a molecule. 
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All of the following are indicators of chemical change except…
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The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:
ololo11 [35]

The allowable combination for the atomic orbital is n=3, l=1 or 2, m_{l}=+1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; m_{l} values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Hence, the l value must be lower than 3. Because of m_{l}= +1, the l value must be higher than 0. Two l values are consistent with n and m_{l) values:

l= 1 or 2

Therefore, the allowable condition is n=7, l=1 or 2, m_{l}=+3.

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

7 0
1 year ago
Describe how to prepare 10 ml of 5, 10, 15, and 20 micro M CV solution using a 25 microM CV stock solution
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