1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DENIUS [597]
2 years ago
8

A 500.0-mL buffer solution is 0.100 M in HNO2 and 0.150 M in KNO2. Determine whether each addition would exceed the capacity of

the buffer to neutralize it.250.0 mg NaOH350.0 mg KOH1.25 g HBr1.35 g HI
Chemistry
1 answer:
Leviafan [203]2 years ago
7 0

Answer:

None of the additions will exceed the capacity of the buffer.

Explanation:

As we know a buffer has the ability to resist pH changes when small amounts of strong acid or base are added.

The pH of the buffer is given by the Henderson-Hasselbach equation:

pH = pKa + log [A⁻] / [HA]

where A⁻ is the conjugate base of the weak acid HA.

Now we can see that what is important is the ratio [A⁻] / [HA] to resist a pH change brought about by the addition of acid or base.

It follows then that once we have consumed by neutralization reaction either the acid or conjugate base in the buffer, this will lose its ability to act as such and the pH will increase or decrease dramatically by any added acid or base.

Therefore to solve this question we must determine the number of moles of acid HNO₂ and NO₂⁻ we have in the buffer and compare it with the added acid or base to see if it will deplete one of these species.

Volume buffer = 500.0 mL = 0.5 L

# mol HNO₂ = 0.5 L x 0.100 mol/L = 0.05 mol HNO₂

# mol NO₂⁻ = 0.5 L x 0.150 mol/L = 0.075 mol NO₂⁻

a. If we add 250 mg NaOH (0.250 g)

molar mass NaOH =40 g/mol

# mol NaOH =0.250 g/ 40g/mol = 0.0063 mol

0.0063 mol NaOH will be neutralized by 0.0063 mol HNO₂ and we have plenty of it, so it would not exceed the capacity of the buffer.

b. If we add 350 mg KOH (0.350 g)

molar mass KOH =56.10 g

# mol KOH = 0.350 g/56.10 g/mol = 0.0062 mol

Again the capacity of the buffer will not be exceeded since we have 0.05 mol HNO₂ in the buffer.

c. If we add 1.25 g HBr

molar mass HBr = 80.91 g/mol

# mol HBr = 1.25 g / 80.91 g/mol = 0.015 mol

0.015 mol Hbr will neutralize 0.015 mol NO₂⁻ and we have to start with 0.075 mol in the buffer, therefore the capacity will not be exceeded.

d. If we add 1.35 g HI

molar mass HI = 127.91 g/mol

# mol HI = 1.35 g / 127.91 g/mol = 0.011 mol

Again the capacity of the buffer will not be exceed since we have plenty of it in the buffer after the neutralization reaction.

You might be interested in
What is anything that has mass and volume
Pavlova-9 [17]
Anything that has mass and volume (takes up space) is called matter.
3 0
3 years ago
Read 2 more answers
Which is the following is a vector quality?<br>ans:<br>1)mass<br>2)speed<br>3)time<br>4)plane area​
Brut [27]

Answer:

speed

Explanation:

hope it helps

keep smiling

4 0
2 years ago
Which tool can be used to measure the volume of a liquid to one decimal place?
pentagon [3]
The tool to measure the liquid is a measuring cylinder.
3 0
2 years ago
Read 2 more answers
What volume of o2 is needed to react fully with 720. Ml of nh3
Galina-37 [17]

Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

Given,

Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O

From the stoichiometry of the reaction, it can be said that,

(4 \times  22.4) L of ammonia reacts with (5 \times  22.4) L of oxygen gas.

So, 0.720 L of  ammonia will react with:

\dfrac{ (5 \times  22.4)}{(4 \times  22.4)} \times 0.720 = 0.9 \;\rm L

Therefore, the volume of oxygen required is 900 mL.

Learn more about volume here:

brainly.com/question/14090111

#SPJ4

6 0
2 years ago
Calculate the distance that a man walked if it took him 42 seconds to walk at a speed of 3m/s.
Hitman42 [59]

Answer:

126 m

Explanation:

Distance=time*speed➡42*3=126m.

7 0
2 years ago
Other questions:
  • A solution of phosphoric acid was made by dissolving 10.0 g of H3PO4 in 100.0 mL of water. The resulting volume was 113 mL. Calc
    6·1 answer
  • What symbol is used to show the standard reduction potential of an oxidation reaction in a half-cell?
    6·1 answer
  • Water has a density 1.0 g/cm3. What is the mass of 10.0 cm3 of water?
    12·1 answer
  • It is nearly impossible to blank solids and liquids
    7·2 answers
  • The solubility of gold (V) oxalate, Au2(C2O4)5 is 2.58 g/L. Calculate Ksp from this information.
    14·1 answer
  • Which of the following molecules contains polar covalent bonds?
    15·1 answer
  • How many moles of magnesium oxide are formed if you burn a 2.3 mol sample of magnesium ribbon in the air? You must show ALL work
    8·1 answer
  • 1. If 2 moles of hydrogen combine with one mole of oxygen, how many moles of water are<br> produced?
    13·1 answer
  •  how are subscripts determine the formula of ionic and covalent compounds ?
    14·1 answer
  • Describe the skier function of the law of conservation of energy
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!