Complete Question:
The mass of the sphere is 0.151 kg. What is the rotational inertia of the wheel? Recall that the radius of the sphere is about 0.312 m. Express your answer with three significant figures in Kg.m².
Answer:
I = 5.88*10⁻³ kg.m²
Explanation:
It can be showed that the rotational inertia (or moment of inertia) for a solid sphere of radius r and mass m, regarding any axis passing through the center of the sphere, can be expressed as follows:
I = (2/5)*m*r² (1)
where m= 0.151 kg, and r =0.312 m. (Our givens).
Replacing in (1) we have:
I = (2/5)*0.151 kg*(0.312m)² = 5.88*10⁻³ kg.m²
MA = output force/input force
MA = 12N / 4N
MA = 3N
Answer:
Mass of the solution = 54.75 g
Explanation:
Mass of solid dissolved = 4.75 g
Mass of the solution = Mass of solid dissolved + Mass of water.
Mass of water = Volume x Density
Volume = 50 mL = 50 cm³
Density = 1 g/cm³
Mass of water = 50 x 1 = 50 g
Mass of the solution = 4.75 + 50 = 54.75 g
Answer:
See explanations
Explanation:
Given that,
Electric field E=135V/m
Energy stored in 1m³of air=?
The energy stored in an electric field is given as
u = ½ εo E²
Where
U is the energy stored
εo is permissivity and it value is 8.85×10^-12C²/N..m²
And E is the electric field
Then,
U=½×8.85×10^-12×135²
U=8.06×10^-8J/m³
Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³
