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romanna [79]
3 years ago
5

On the basis of bonding, which of the following is true about calcium chloride when

Chemistry
2 answers:
olganol [36]3 years ago
6 0

its A, calcium chloride has a higher boiling point than sucrose

alexgriva [62]3 years ago
5 0

Answer:

A

Explanation:

Calcium chloride has a higher boiling point than sucrose.

Just took the test!

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Which pair of elements would most likely form a covalent bond
denpristay [2]

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Nonmetals and nonmetals tend to form covalent bonds.

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P and S

Explanation:

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A compound was found to be soluble in water. It was also found that addition of acid to an aqueous solution of this compound res
gogolik [260]

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c. Cr

Explanation:

Cr^3+(aq) + CO_3^2-(aq) ------------> Cr_2CO_3(s)

The compound is containing CO_3^2- ion.

If acid reacts with it, CO_2 evolves.

H^+ + CO_3^2- ----------> H_2O + CO_2

therefore,  Cr would form a precipitate when added to an aqueous solution of this compound. Cr2CO3 is the precipitate.

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3 years ago
Wood, Iron, Glass, Paper, Nickel Which substances show magnetic property?
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3 years ago
When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, what hybrid orbitals are used by p
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When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, hybrid orbitals that  are used by phosphorus in the pcl4 cations are one orbital of s and three orbital of p as it is sp³hydridised.

<h3>What is sp³ hybridization?</h3>

Hybridization is a process or system which specifies the shape and geometry of any element or molecule with bond angles too.

The pcl4 cation is sp³ hybridized because of the phosphorus behave as a central atom here and the 4 chloride molecules are attached with the p- orbitals to the phosphorus molecule.

Therefore, pcl4 cation  is sp³ hybridized.

Learn more about sp³ hybridization, here :

brainly.com/question/13062274

#SPJ4

5 0
2 years ago
Fdsddddgdgdgdgsdggd.
larisa [96]
Fdsddadgdsadgsd:
Fasdadasdfadsdfasdf asfsadafasdfasdffdaddad dads fdfgdfgfdg

Fdgdfgdfgdgfggggfg gdfgdfgd:
Fgdfgdfgdfgrdfhdf hdfgdfhdfh == fhdfgdfh /fhdgdg .
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