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nataly862011 [7]
2 years ago
9

48.5 moles of P4O10 contains how many moles of P

Chemistry
2 answers:
larisa [96]2 years ago
7 0

Answer : The number of moles of phosphorous are 194 moles.

Explanation : Given,

Moles of P_4O_{10} = 48.5 moles

By the stoichiometry in P_4O_{10}, there are 4 moles of phosphorus and 10 moles of oxygen.

As, 1 mole of P_4O_{10} contains 4 moles of phosphorous

So, 48.5 moles of P_4O_{10} contains 48.5\times 4=194 moles of phosphorous

Therefore, the number of moles of phosphorous are 194 moles.

EastWind [94]2 years ago
3 0
So moles P = 4 x moles P4O10 
= 4 x 68.5 mol 
= 274 mol
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What alkene(s) would be produced from the dehydration of cyclopentanol?
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The dehydration of cyclopentanol is shown in the balanced equation below:

Cyclopentanol => cyclopentene + H2O

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3 years ago
Using the average initial pH of your acetic acid solutions (2.96), and the average molarity of those solutions(.0602), calculate
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Answer : The value of Ka for acetic acid is,  2.03\times 10^{-5}

Explanation :

The chemical formula of acetic acid is, CH_3COOH.

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pH=-\log [H^+]

2.96=-\log [H^+]

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The expression for reaction is:

K_a=\frac{[CH_3COO^-][H^+]}{[CH_3COOH]}

K_a=\frac{(1.096\times 10^{-3})\times (1.096\times 10^{-3})}{0.0591}

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isotopes are various forms of same elements with different atomic number but different mass number.

Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are

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in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.

Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below

\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right +  \left \{ {{y=0} \atop {x=0}}γ\right.

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